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makkiz [27]
3 years ago
7

Formula for revolution​

Physics
1 answer:
OleMash [197]3 years ago
3 0

Answer: degrees divided by 360

Explanation:

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The following equation is an example of decay?<br><br> 232/90 TH---4/2 HE +228/88 RA?
DaniilM [7]

Answer:

Alpha decay

Explanation:

  • Alpha decay is one of the three major types of decays, others being, beta decay and gamma decay.
  • <em><u>When a radioactive isotope undergoes alpha decay it emits alpha particles. An alpha particle is equivalent to the nucleus of Helium atom.</u></em>
  • <em><u>Therefore, an atom undergoing decay, its atomic mass is decreased by 4 and its atomic number is decreased by 2. </u></em>
  • Thus, since 232/90 Th, has undergone alpha decay its mass number is reduced by 4 to 228 and its atomic number by 2 to 88, and becomes 228/88 Ra.
5 0
3 years ago
A car accelerate uniformly from rest at 5m/s2 . Determine it's speed after 10s​
krek1111 [17]

Answer:

50m/s.

Explanation:

Let's take acceleration as A and speed as S:

A = 5m/s²

S = A × 10s = 5 × 10 = 50m/s

The answer is 50m/s.

6 0
4 years ago
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How is this career a good fit for you or an individual who would work in this field
kiruha [24]

Answer:

Which career is it?

4 0
4 years ago
Problem 7.17 A horizontal spring with stiffness 0.8 N/m has a relaxed length of 12 cm (0.12 m). A mass of 23 grams (0.023 kg) is
Jlenok [28]

The speed of the mass v = 0.884 m/s.

<u>Explanation</u>:

Let

K1 represents the kinetic energy of the mass when it is released,

U1 represents the potential energy of the spring when the mass is released,

K2 represents the kinetic energy of the mass when the spring returns to relaxed length,

U2 represents the potential energy of the spring when the spring returns to relaxed length

The spring is stretched by 0.27 - 0.12 = 0.15 m

                                K1 = 0

                                 U1 = (1/2) \times 0.8 \times (0.15)^2

                                     = 0.009 J

                                U2 = 0

By conservation of energy,

                        K2 + U2 = K1 + U1

                           K2 + 0 = 0 + 0.009 J

                                 K2 = 0.009 J

Let v = speed of the mass

                                K2 = 1/2 \times m \times v^2

m = 23 g = 0.023 kg

                           0.009 = 1/2 \times 0.023 \times v^2

                           0.009 = 0.0115 \times v^2

                                   v = √(0.009 / 0.0115)

                                  v = 0.884 m/s.

5 0
4 years ago
A block of cheese is resting on an incline.
andreev551 [17]

Answer:

The answer is diagram B I tried it out and it worked

Explanation:

4 0
3 years ago
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