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nika2105 [10]
3 years ago
10

What time that take if wavelength 1/10^8 and 3*10^8 m/s?

Physics
1 answer:
asambeis [7]3 years ago
5 0

Answer:3.33x10^(-17)

Explanation:

Period=wavelength ➗ velocity

Period=1/10^8 ➗ (3x10^8)

Period=3.33x10^(-17)

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A truck traveling with an initial velocity of 22m/s comes to a stop in 17.32 secs. What is the acceleration of the truck?
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Explanation:

Given:

v₀ = 22 m/s

v = 0 m/s

t = 17.32 s

Find: a

v = at + v₀

(0 m/s) = a (17.32 s) + (22 m/s)

a = -1.270 m/s²

Round as needed.

6 0
2 years ago
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A person carries a plank of wood 2 m long with one hand pushing down on it at one end with a force F1 and the other hand holding
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3 years ago
The focal length of a lens is inversely proportional to the quantity (n-1), where n is the index of refraction of the lens of th
Ainat [17]

Answer:

46.22 cm

Explanation:

The focal refraction, fr is given by

fr = \frac {c}{(1.572 -1)}  = \frac {c}{0 .572}  

The focal red light is given by

fv = \frac {c}{(1.605 - 1)} = \frac {c}{0.605}

\frac {fv}{fr} = \frac {0.572}{0 .605} = 0.945455

\frac {1}{fr} = \frac{1}{image} + \frac {1}{object} and making fr the subject we obtain

fr = \frac {image * object}{(image + object)} = \frac {24.00 * 55} {(24.0 + 55)} = 16.70886 cm

fv = 0.945455* 16.70886 cm = 15.79747 cm

image = \frac {object * f} {(object - f)} = \frac {15.79747 * 24.0}{(24.0 - 15.79747)} = 46.22222 cm

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5 0
3 years ago
What is the relationship among
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The bigger the object the greater the gravitational pull, so the farther away the big object is its gravitational force begins to decrease. Refer to the picture for more explanation.

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