Question

A freighter carrying a cargo of uranium hexafluoride sank in the English Channel in late August 1984. The cargo of uranium hexafluoride weighed 2.25 x 108 kg and was contained in 30 drums, each having a volume of 1.62 x 106 L. What is the density (g/mL) of uranium hexafluoride?

Answer 1

Answer:

$\rho = 4.63 g/mL$

Explanation:

Volume of each drum in which the Uranium Hexafluoride is contained is given as

$V = 1.62 \times 10^6 L$

$V = 1.62 \times 10^9 mL$

now we know that mass of the uranium is given as

$m = 2.25 \times 10^8 kg$

now total volume of all 30 containers is given as

$V = 30 (1.62 \times 10^9)$

$V = 4.86 \times 10^{10} mL$

$m = 2.25 \times 10^{11} g$

so now the density is given as

$\rho = \frac{m}{V}$

$\rho = \frac{2.25 \times 10^{11}}{4.86 \times 10^{10}}$

$\rho = 4.63 g/mL$