All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Answer: 11x1.5=16.5 if im correct
Step-by-step explanation:B)
Answer:
298.258
Step-by-step explanation:
- 8×60 =480 ÷1.609
ANSWER
The correct answer is C
.
<u>EXPLANATION</u>
We have

and
.
We solve the two equation simultaneously by elimination method. We need to be smart and eliminate y, since we are looking for
.
We first multiply equation (2) by 2
.
We add equation (3) and (1).
.
Dividing through by 6 gives
.