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jek_recluse [69]
3 years ago
12

How many grams of O are in 765 g of N,O?​

Chemistry
2 answers:
Nastasia [14]3 years ago
8 0

Answer: 278grams, assuming N,O is actually N2O.

Explanation: Is "N,O" really supposed to read NO or N2O? This assumes N2O, laughing gas. I see another post used NO, so the problem is covered either way.

The molar mass of N2O is 44 g/mole. 765g would be 17.38 moles of N2O. That means we also have 17.38 moles of O. The molar mass of O (not O2) is 16 g.mole.

(17.38 moles(*(16 g/mole) = 278 grams of O

Another approach is to calculate the percentage of O in N2O:

N: 2*14 = 28

O: 1*16 = 16

N2O: = 44

% O is 16/44 = 36.3%

0.363*765 = 278 grams (same answer)

elena-s [515]3 years ago
6 0

Answer:

408g

Explanation:

Relative atomic mass of NO: 14+16 =30

16/30*100= 53.3%(percentage by mass of O in NO)

53.3/100*765= mass of O

=408g

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