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Zinaida [17]
3 years ago
11

3.0 moles of nitrogen is reacted with 11.0 moles of hydrogen to produce ammonia according to the chemical equation shown below.

Which one of the following statements is false?
N2(g) + 3 H2(g) → 2 NH3(g)
a. Hydrogen is the excess reactant.
b. 2.0 moles of hydrogen are left over.
c. 12.0 moles of ammonia are produced.
d. Nitrogen is the limiting reactant.​
Chemistry
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer:

c

Explanation:

From the equation, we can say that we need thrice the number of hydrogen than that of nitrogen

we are given 3 moles of nitrogen and 11 moles of hydrogen

but thrice the number of moles of nitrogen is 9, hence we have hydrogen in excess or Hydrogen is the excess reagent

Since we had 11 moles of Hydrogen and we only needed 9, 2 moles of hydrogen are left over

From the equation, we can see that the moles of ammonia formed will be twice the moles of nitrogen

Since 3 moles of nitrogen are used, the reaction will give us 6 moles of Ammonia and NOT 12 moles, therefore c is the correct answer

Since we have hydrogen in excess, our reaction is being limited because we have less Nitrogen, Hence Nitrogen is the Limiting Reagent

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3 years ago
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Calculate how many valence electrons are in H2CO, N2, Cl2?
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6 0
3 years ago
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A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a
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The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

q=mc\Delta T

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

q_{released}=q_{absorbed}\\&#10;q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T

The given mass of calorimeter has been, m_{calorimeter}=1350\;\rm g

The specific heat of the calorimeter has been, c_{calorimeter}=5.82\;\rm J/g^\circ C

The change in temperature of the calorimeter has been, \Delta T=2.87^\circ \rm C

Substituting the values for heat released:

q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\&#10;q_{released}=22,549.5\;\text J\\&#10;q_{released}}=22.54\;\rm kJ

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

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6 0
3 years ago
What is the mass in grams of 0.000142 mol of vitamin c
bazaltina [42]

Answer:

0.0250 g

Explanation:

Step 1: Determine the molar mass of Vitamin C.

The molar mass is the mass in grams corresponding to 1 mole. In order to calculate the molar mass of vitamin C (C₆H₈O₆) we need to add the molar masses of the elements that compose it.

M(C₆H₈O₆) = 6 × M(C) + 8 × M(H) + 6 × M(O)

M(C₆H₈O₆) = 6 × 12.01 g/mol + 8 × 1.01 g/mol + 6 × 16.00 g/mol

M(C₆H₈O₆) =  176.14 g/mol

Step 2: Calculate the mass corresponding to 0.000142 mol of vitamin C.

0.000142 mol \times \frac{176.14g}{mol} =0.0250 g

7 0
3 years ago
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