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Licemer1 [7]
3 years ago
5

Explain the four phases of cell division

Chemistry
2 answers:
LekaFEV [45]3 years ago
5 0

Mitosis takes place in four stages: prophase (sometimes divided into early prophase and prometaphase), metaphase, anaphase, and telophase.

Mitosis is the process in which the nucleus of a eukaryotic cell divides. During this process, sister chromatids separate from each other and move to opposite poles of the cell. This happens in four phases, called prophase, metaphase, anaphase, and telophase

Anon25 [30]3 years ago
3 0

Answer:

The four phases of cell division are prophase, metaphase, anaphase and telophase.

Explanation:

During the prophase, mitotic spindle begins to form. the chromosomes start to condence and the nucleus disappears.

During the metaphase, the chromosomes align themselves in the moddle of the cell. They form a metaphase plate by this alignment.

During anaphase, the sister chromatids are pulled towards the opposite poles by the microtubules.

During the telophase,  chromatids have been equally divided to each part. Hence, the mitotic spindle breaks down. Nuclear membranes forms again around the two daughter cells.

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Given:
Stock dose/concentration of 20% Acetylcysteine (200 mg/mL)
150 mg/kg dose of Acetylcysteine
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First we must convert 13.2 lb to kg:
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Then we must calculate the dose:
(150 mg/kg)(6kg) = 900 mg

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3 0
3 years ago
Kinematics equations are used only by physicists and people who work in
nevsk [136]

Answer:

FALSE

Explanation:

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5 0
3 years ago
Read 2 more answers
A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4
natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M

8 0
3 years ago
What should be included in a science conclusion
QveST [7]
A science conclusion should simply have a statement identifying whether your experiment’s aim turned out to be true or false
7 0
2 years ago
KClO3 (s) KCl (s) + 02 (g)​<br><br><br>How do you balance this equation
Vitek1552 [10]

Answer:

2KCl(s) + 6O3O2

Explanation:

I think it's correct

7 0
3 years ago
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