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Licemer1 [7]
3 years ago
5

Explain the four phases of cell division

Chemistry
2 answers:
LekaFEV [45]3 years ago
5 0

Mitosis takes place in four stages: prophase (sometimes divided into early prophase and prometaphase), metaphase, anaphase, and telophase.

Mitosis is the process in which the nucleus of a eukaryotic cell divides. During this process, sister chromatids separate from each other and move to opposite poles of the cell. This happens in four phases, called prophase, metaphase, anaphase, and telophase

Anon25 [30]3 years ago
3 0

Answer:

The four phases of cell division are prophase, metaphase, anaphase and telophase.

Explanation:

During the prophase, mitotic spindle begins to form. the chromosomes start to condence and the nucleus disappears.

During the metaphase, the chromosomes align themselves in the moddle of the cell. They form a metaphase plate by this alignment.

During anaphase, the sister chromatids are pulled towards the opposite poles by the microtubules.

During the telophase,  chromatids have been equally divided to each part. Hence, the mitotic spindle breaks down. Nuclear membranes forms again around the two daughter cells.

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Explain what happens when something dissolves.
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During dissolving, particles of solvent collide with particles of solute. They surround the particles of solute, gradually moving them away until the particles are evenly spread through the solvent.

6 0
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Which of the following statements is correct about the gases which participate in photosynthesis?
Sidana [21]
If you look at the equation for photosynthesis, it is:
<span>6CO2 + 6H2O + light energy ---> C6H12O6 + 6O2
</span>
Since CO2 (carbon dioxide) is on the left side of the equation, it is being consumed, or used up. Since O2 (oxygen) is on the right side, it is being produced.

The correct answer is the first one, "<span>Carbon dioxide is used up, and oxygen is produced."</span>
7 0
3 years ago
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In a nuclear fission reaction, a freely moving neutron is introduced to a nuclear fuel, such
insens350 [35]

In a nuclear fission reaction, a freely moving neutron is introduced to a nuclear fuel, then a neutron is absorbed by an atom's nucleus.

<h3>What is nuclear fission?</h3>

Nuclear fission is a process in which an unstable nuclei will convert into stable nuclei after releasing the energy in the form of particles.

When we introduce a freely moving neutron to the nuclear fuel of uranium-235 nuclei then this introduced neutron was absorbed by the nuclei and makes the nuclei more unstable. Then this unstable nuclei will convert into two nuclei in the addition of three neutrons.

Hence, a neutron is absorbed by an atom's nucleus.

To know more about nuclear fission, visit the below link:

brainly.com/question/14019172

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6 0
1 year ago
The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Delicious77 [7]

<u>Answer:</u>

<u>For a:</u> The edge length of the crystal is 533.5 pm

<u>For b:</u> The atomic radius of potassium is 231.01 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the lattice parameter or edge length of the crystal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 0.855g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal = 39.09 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell = ?

Putting values in above equation, we get:

0.855=\frac{2\times 39.09}{6.022\times 10^{23}\times (a)^3}\\\\\a=5.335\times 10^{-8}cm=533.5pm

<u>Conversion factor:</u>  1cm=10^{10}pm

Hence, the edge length of the crystal is 533.5 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 533.5 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 533.5}{4}=231.01pm

Hence, the atomic radius of potassium is 231.01 pm

4 0
3 years ago
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