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suter [353]
3 years ago
15

Is it possible to make CD without plastic? why or why not?

Chemistry
2 answers:
Kisachek [45]3 years ago
5 0
I think it is not possible to make cd without plastic . because except plastic no other material is so durable for making cd.
padilas [110]3 years ago
4 0
No, its not possible because mostly substances are not durable also u can take an example of iron. if we make a cd of iron then rusting occurs
hope it helps u
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BRAINLIEST AWARD PLZ HELP :)
Vera_Pavlovna [14]
Properties of metals:
High melting points
High density
Ductile
Malleable
Good conductors of electricity
Good conductors of heat


I think if you added a proton you would have chlorine.


The noble gasses are the he chemical elements in group 18 of the periodic table. The gasses in this family include helium, neon, argon, krypton, xenon, and radon. All these gasses are colorless are oderless, elements in this family have atoms with a full outer shell of electrons. They are also called inert gasses.

Six valence electrons
6 0
3 years ago
Read 2 more answers
Help with number 20-22 please
SSSSS [86.1K]
18. c
19. A
20. decomposition reaction 
21. 4 
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4 0
3 years ago
It takes 338. kJ/mom to break a carbon-chlorine single bond. Calculate the maximum wavelength of light for which a carbon-chlori
Vesnalui [34]

Answer: The maximum wavelength of light for which a carbon-chlorine Single bond could be broken by absorbing a single photon is 354 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{Nhc}{\lambda}

where,

E = energy of the light  = 338kJ=338000J    (1kJ=1000J)

N= avogadro's number

h = Planck's constant

c = speed of light

\lambda = wavelength of light

338\times 1000J=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^{8}}{\lambda}    

{\lambda}=0.354\times 10^{-6}m=354nm     (1nm=10^{-9}m

Thus the maximum wavelength is 354 nm

6 0
3 years ago
2.20 moles Sn to grams
mihalych1998 [28]
261.162 grams. Use the equation n=M÷Mr.
3 0
3 years ago
20.0 g of bromic acid, HBrO3, is reacted with excess HBr.
Blababa [14]

After Rounding off The percentage yield is 64%

<h3>What is Percentage Yield ?</h3>

It is the ratio of actual yield to theoretical yield multiplied by 100% .

It is given in the question

20.0 g of bromic acid, HBrO3, is reacted with excess HBr.

The reaction is

HBrO₃ (aq) + 5 HBr (aq) → 3 H₂O (l) + 3 Br₂ (aq)

Actual yield = 47.3 grams

Molecular weight of Bromic Acid is 128.91 gram

Moles of Bromic Acid = 20/128.91 = 0.155 mole

Mole fraction ratio of Bromic Acid to Bromine is 1 :3

Therefore for 0.155 mole of Bromic Acid 3 * 0.155 = 0.465 mole of Bromine is produced.

1 mole of Bromine = 159.8 grams of Bromine

0.465 of Bromine = 74.31 grams of Bromine

Percentage Yield = (47.3/74.31)*100 = 63.65 %

After Rounding off The percentage yield is 64% .

To know more about Percentage Yield

brainly.com/question/22257659

#SPJ1

5 0
1 year ago
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