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marusya05 [52]
2 years ago
9

How many moles are equal to 7.62 x 1025 molecules lithium hydroxide​

Chemistry
1 answer:
ycow [4]2 years ago
8 0

No of moles:-

\\ \tt\longmapsto \dfrac{No\:of\:atoms}{Avagadro's\; number}

\\ \tt\longmapsto \dfrac{7.62(10^{25})}{6.022(10^{23})}

\\ \tt\longmapsto 126.5mol

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Neporo4naja [7]

Answer:

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Explanation:

7 0
2 years ago
Read 2 more answers
A 10.0-gram sample of liquid water at 23.0°C absorbs 209 joules of heat.
Aliun [14]

Answer:

The final temperature of the water is 28.0 °C

Explanation:

Step 1: Data given

Mass of liquid water = 10.0 grams

Temperature = 23.0 °C

Heat absorbed = 209 Joules

Since heat was absorbed by the water, you must have a positive value for  

Δ T

Step 2: Calculate final temperature

q = m*c* ΔT

⇒ with m = the mass of the water = 10.0 grams

⇒ with c = the specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature = T2 -  T1 = T2 - 23.0 °C

⇒ with q = the heat absorbed = 209 Joule

209 = 10.0 * 4.184 * ΔT

ΔT = 5

ΔT = 5 = T2 - 23

T2 = 28 °C

The final temperature of the water is 28.0 °C

8 0
3 years ago
If each jar below contains exactly one mole of each element, which jar contains the greatest mass? (The atomic mass of each elem
k0ka [10]

B.

The jar of sulfur.

Explanation:

The molar mass of sulfur is 32 g/mol

The molar mass of Aluminium is 27g/mol

The molar mass of carbon is 12 g/mol

Therefore based on these numbers, it is evident that a mole of Sulfur weighs the heaviest.

Different elements weight different because their atoms have different mass numbers. The lower you go in the periodic table the heavier the atoms became because they have more atomic units (neutrons and protons) in their nuclei.

4 0
3 years ago
What is the formula for the precipitate when solutions of manganese (II) nitrate and
natita [175]

The precipitate formed when a solution of manganese(II) nitrate and

potassium sulfide react is Manganese sulfide (MnS)

To obtain the precipitate formed when a solution of manganese(II) nitrate and potassium sulfide react, we shall write the balanced ionic equation. This is illustrated below:

Manganese (II) nitrate => Mn(NO₃)₂

Potassium sulfide => K₂S

In solution, they will react as follow:

Mn(NO₃)₂ (aq) —> Mn²⁺(aq) + 2NO₃¯(aq)

K₂S(aq) —> 2K⁺(aq) + S²¯(aq)

Mn(NO₃)₂ (aq)  + K₂S(aq) —>  

Mn²⁺(aq) + 2NO₃¯(aq) + 2K⁺(aq) + S²¯(aq) —> MnS(s) + 2K⁺(aq) + 2NO₃¯(aq)

Cancel out the spectator ions (i.e K⁺ and NO₃¯)

Mn²⁺(aq) + S²¯(aq) —> MnS(s)

From the net ionic equation above, we can see that MnS is insoluble.

Therefore, the precipitate formed when a solution of manganese(II) nitrate and potassium sulfide react is Manganese sulfide (MnS)

Learn more: brainly.com/question/21280827

6 0
2 years ago
Select all that apply.
kondaur [170]
Enzymes are catalysts in chemical reactions.
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