Answer:
a=0
∑Fx = 0
Explanation:
Known data
m =1.7 kg : jeep's mass
θ = 12° :angle of the slope with respect to the horizontal direction
g = 9.8 m/s² : acceleration due to gravity
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
We define the x-axis in the direction parallel to the movement of the block on the ramp and the y-axis in the direction perpendicular to it.
Calculated of the W
W= m*g
W= 1.7 kg* 9.8 m/s² = 16.66 N
x-y weight components
Wx= Wsin θ= 16.66*sin 12° = 3.45 N
Wy= Wcos θ =16.66*cos 12° = 16.3 N
a) Because the toy jeep lowers the ramp at a constant speed, then, its acceleration is equal to zero.
a=0
b)We apply the formula (1) to calculated ΣFx
∑Fx = m*a , a=0
∑Fx = 0
Correct free-body diagram is option A)
Explanation:
There are three forces acting on Patricia:
- Her weight, which is the force of gravitational attraction exerted by the Earth on her, whose magnitude is
(where m= mass and g= acceleration of gravity). The direction of this force is vertically downward. - The normal force, exerted by the plane on Patricia, which acts always up perpendicular to the plane
- The force of friction, which prevents Patricia from sliding. The force of static friction acts in the direction opposite to the direction of motion if the body is let moving: so here, the force of friction acts up along the plane (parallel to the plane)
Therefore, the correct choice here is option A), because:
- The weight acts vertically downward
- The normal force acts perpendicular to the plane
- The force of friction acts parallel to the plane
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Answer:
FORCE as for my answer....