Given data:
Diameter of the gold wire (d) = 0.175 cm
Length of the gold wire (l) = 1.00 *
cm
Volume of the given gold wire = volume occupied by a cylindrical object\
= π *
*l
here r = radius of the cross section
where : r = d/2
Hence the volume V = π *
*l
= 
Density of gold = 19.3 g/cm3
Weight of the gold wire = Density * volume
=
*
= 
The atoms will form intermolecular bonds and solidify
Hydrogen peroxide decomposes to yield water and oxygen gas
That is; H2O2 (l) = H2O (l) + O2(g)
The standard heat of formation; H2O2 (l) = -187.6 kJ/mol; H2O(l) = -285.8 kJ/mol
1 mole of hydrogen peroxide contains 34 g
Thus, 5.4 g contains 5.4/34 = 0.1588 moles
The moles of water produced will also be equivalent to 0.1588 moles
Heat = heat of formation of product - reactant
Therefore; Heat = (0.1588 moles × -285,8 )- (0.1588× -187.6)
= -15.594 kJ
<span>work = force x distances </span>
<span>A - moving 2 newton's up 0.6 meter = 1.2 joules
B - moving 4 newton's up 0.6 meter = 2.4 joules
C - moving 6 newton's up 0.3 meter = 1.8 joules
D - moving 9 newton's up 0.3 meter = 2.7 joules
The greatest amount of work is in example D.
</span>
<span>
D is your answer. </span>
your answer is <u>D</u><u>.</u><u> </u>physical change, because a new substance is not formed.