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Kipish [7]
3 years ago
15

25 – 30 Apply the appropriate word to the definition indicated. Not all words will be used. 25. _____ Heat content of a system a

t constant pressure calorie (cal) 26. _____ Ability to do work Chemical Potential Energy 27. _____ Disorder Energy 28. _____ Energy of motion Enthalpy 29. _____ Study of energy changes that ocrrue during chemic reaction and changes in states. Entropy 30. _____ Amount of heat required to raise T of 1 g of pure water 1◦C Joule Kinetic energy Heat (q) Specific Heat Thermochemistry
Chemistry
1 answer:
masha68 [24]3 years ago
4 0
<span>25. _____ Heat content of a system at constant pressure calorie (cal) ---> Enthalpy

26. _____ Ability to do work Chemical ----> Energy

 27. _____ Disorder ----> Entropy

28. _____ Energy of motion ----> Kinetic energy

29. _____ Study of energy changes that ocrrue during chemic reaction and changes in states. ----> Thermochemestry

30. _____ Amount of heat required to raise T of 1 g of pure water 1◦C ----> Specific heat</span>
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Chemical would be the correct answer
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For a particular chemical reaction, the enthalpy of the reactants is -400 kJ. The enthalpy of the products is -390 kJ. The entro
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Answer:

For a particular chemical reaction, the enthalpy of the reactants is -400 kJ. The enthalpy of the products is -390 kJ. The entropy of the reactants is 0.2 kJ/K. The entropy of the products is 0.3 kJ/K. The temperature of the reaction is 25oC. What can you conclude about this reaction?

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2 years ago
Combustion reactions are exothermic. The heat of reaction for the combustion of 2-methylheptane, C8H18, is 1.306×103 kcal/mol. W
WARRIOR [948]

Answer:

11.45kcal/g

2.612 × 10³ kcal

Explanation:

When a compound burns (combustion) it produces carbon dioxide and water. The combustion of 2-methylheptane can be represented by the following balanced equation:

2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O

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<em>What is the heat of combustion for 2-methylheptane in kcal/gram?</em>

We know that the molar mass of C₈H₁₈ is 114.0g/mol. Then, using proportions:

\frac{1.306 \times 10^{3}Kcal}{1mol} .\frac{1mol}{114.0g} =11.45kcal/g

<em>How much heat will be given off if molar quantities of 2-methylheptane react according to the following equation? 2 C₈H₁₈ + 25 O₂ ⇄ 16 CO₂ + 18 H₂O</em>

In this equation we have 2 moles of C₈H₁₈. So,

2mol \times\frac{1.306 \times 10^{3}kcal }{1mol} =2.612\times 10^{3}kcal

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