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In-s [12.5K]
2 years ago
12

Balance the combustion reaction between octane and oxygen. 2C8H18 + O2 → CO2 + H2O

Chemistry
2 answers:
Ber [7]2 years ago
6 0

Explanation:

A balanced reaction is a reaction where there are equal number of atoms on both reactant and product side.

For example, 2C_{8}H_{18} + O_{2} \rightarrow CO_{2} + H_{2}O

Number of atoms on reactant side are as follows.

  • C = 16
  • H = 36
  • O = 2

Number of atoms on product side are as follows.

  • C = 1
  • H = 2
  • O = 3

Therefore, in order to balance the equation we multiply O_{2} by 25 on reactant side and multiply CO_{2} by 16 and H_{2}O by 18.

Thus, the balanced chemical equation will be as follows.

       2C_{8}H_{18} + 25O_{2} \rightarrow 16CO_{2} + 18H_{2}O

nika2105 [10]2 years ago
5 0
The answer is 2C8H18 + 25O2 ⇒ 16CO2 + 18H2O<span />
You might be interested in
Ethyl acetate reacts with H2, in the presence of a catalyst to yield ethyl alcohol: C4H8O2 + 2H2--&gt; 2C2H6O. A. How many grams
Anni [7]
The balanced chemical reaction is:

<span>C4H8O2 + 2H2--> 2C2H6O

</span>A. How many grams of ethyl alcohol are produced by reaction of 2.7 mol of ethyl acetate with H2? 2.7 mol C4H8O2 ( 2 mol C2H6O / 1 mol C4H8O2) (46.07 g / 1 mol) = 248.78 g ethyl alcohol

B. How many grams of ethyl alcohol are produced by reaction of 13.0g of ethyl acetate with H2?
13.0 g C4H8O2 ( 1 mol / 88.11 g) ( 2 mol C2H6O / 1 mol C4H8O2) (<span>46.07 g / 1 mol) = 13.59 g ethyl alcohol</span>

C. How many grams of H2 are needed to react with 13.0g of ethyl acetate?
13.0 g C4H8O2 ( 1 mol / 88.11 g) ( 2 mol H2 / 1 mol C4H8O2) (2.02 g / 1 mol) = 0.5961 g H2
6 0
3 years ago
Element Y has two natural isotopes Y-63 (62.940 amu) and Y-65 (64.928 amu). Calculate the atomic mass of element Y, given the ab
djverab [1.8K]

Answer:

Average atomic mass = 63.553 amu.

Explanation:

Given data:

Abundance of Y-63 = 69.17%

Abundance of Y-65 = 100 - 69.17 = 30.83%

Atomic mass of Y-63 = 62.940 amu

Atomic mass of Y-65 = 64.928 amu

Atomic mass of Y = ?

Solution:

Average atomic mass= (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass= (62.940×69.17)+(64.928×30.83) /100

Average atomic mass =  4353.560 + 2001.730 / 100

Average atomic mass = 6355.29 / 100

Average atomic mass = 63.553 amu.

5 0
3 years ago
1.How many milliliters of an aqueous solution of 0.157 M aluminum bromide is needed to obtain 13.4 grams of the salt?
trasher [3.6K]

Answer:

The answer to your question is:

1.- 320 ml

2.- 0.63 M

Explanation:

Data

V = ?   AlBr₃ = 0.157 M

mass = 13.4 g

Process

MW ALBr₃ = 27 + (80x3) = 267 g

                                267 g -------------------- 1 mol

                                13.4 g   ------------------  x

                                x = (13.4 x 1) / 267

                               x = 0.05 moles

Volume = 0.05/ 0.157

             = 0.320 l or 320 ml

2.-

NaNO₃ mass = 20.2 g

V = 375 ml

Molarity = ?

MW = 23 + 14 + 48 = 85g of NaNO₃

                          85 g of NaNO₃ -----------------   1 mol

                          20.2 g               -----------------   x

                         x = (20.2 x 1) / 85

                         x = 0.24 mol

Molarity = 0.24 / 0.375

             = 0.63                

4 0
2 years ago
Explain how you would expect the strength of
LekaFEV [45]

Answer:

  • <u><em>You should expect that the ionic bond in LiBr is stronger than the bond in KBr.</em></u>

<u><em /></u>

Explanation:

The<em> ionic bonds</em> are formed by the electrostatic attraction between the ions, cations and anions.

In KBr the cation is K⁺ and the anion is Br⁻.

In LiBr the cation is Li⁺ and the anion is Br⁻.

You must expect that the bond strength depends mainly on the charges present on each ion and the distance between them.

Nevertheless, the effect of the distance between the radius dominate the trendency of the bond strength, which makes that the ionic strength trend be related to the ionic radius trend.

Lithium is a smaller ion than Potassium (both are in the same group and Lithium is above Potassium).

Thus, you should expect that the Li ion is closer to the Br ion than what the K ion is to the Br ion and expect that the bond between a Li ion and the Br ion be stronger than the bond between the K ion and the Br ion.

6 0
3 years ago
Because Mg and O2 are both elements, no bonds were broken during the formation of MgO.
masya89 [10]

Answer:

false

Explanation

The chemical bonds were broken when creating the compound MgO.

4 0
3 years ago
Read 2 more answers
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