All categories

3 years ago

a body starts from rest and accelerates uniformly at 5ms‐2. Calculate the time taken by the body to cover a distance of 1km

Physics

2 answers:

mixas84 [53]3 years ago

7 0

The body will take 20 seconds to cover a distance of 1000 m i.e. 1 km

bagirrra123 [75]3 years ago

3 0

it may help you have a great day

You might be interested in

A speaker at the front of a room and an identical speaker at the rear of the room are being driven at 456 Hz by the same sound s

vampirchik [111]

Answer:

2.97795 Hz

Explanation:

v = Speed of sound in air = 343 m/s

$v_r$ = Relative speed between the speakers and the student = 1.12 m/s

$f'$ = Actual frequency of sound = 456 Hz

Frequency of sound heard as the student moves away from one speaker

$f_1=f'\dfrac{v-v_r}{v}\\\Rightarrow f_1=456\dfrac{343-1.12}{343}\\\Rightarrow f_1=454.51102\ Hz$

Frequency of sound heard as the student moves closer to the other speaker

$f_2=f'\dfrac{v+v_r}{v}\\\Rightarrow f_2=456\dfrac{343+1.12}{343}\\\Rightarrow f_2=457.48897\ Hz$

The difference in the frequencies is

$f_2-f_1=457.48897-454.51102=2.97795\ Hz$

The student hears 2.97795 Hz

6 0

3 years ago

A mining company plans to improve the infrastructure in a location to start mining activities. The company calculated the costs

vfiekz [6]

To decide whether any project is economically feasible or not, the profit from selling the product needs to be greater than the cost of actually producing or making the product.

In the given question, our project is mining.
The total costs for the project = A + B + C + D + E
The total profit for the project = F

Therefore, to verify that the project is economically feasible, the profit (F) needs to be greater that the cost (A + B + C + D + E)

Based on the above, the best choice would be:
<span>a. by confirming that F is greater than A + B + C + D + E</span>

5 0

3 years ago

Consider two parallel wires where the magnitude of the left currentis 2 I0(io) and that of the right current is I0(io). Point A

balu736 [363]

Answer:

Explanation:

At the point midway between wires

magnetic field due to wire having current 2I₀

= 10⁻⁷ x 2 x2I₀ / r where 2r is the distance between wires .

magnetic field due to wire having current I₀

= 10⁻⁷ x 4 I₀ / r

magnetic field due to wire having current I₀

= 10⁻⁷ x 2I₀ / r

= 10⁻⁷ x 2 I₀ / r where 2r is the distance between wires .

these fields are in opposite direction as direction of current is same in both .

net magnetic field = (4 - 2 )x 10⁻⁷ x I₀ / r

= 2 x 10⁻⁷ x I₀ / r

At point A net magnetic field = 2 x 10⁻⁷ x I₀ / r

At point B , we shall calculate magnetic field

magnetic field due to nearer wire having current 2 I₀ = 10⁻⁷ x 4 I₀ / r

magnetic field due to wire far away = 10⁻⁷ x 2 I₀ / 3r

These magnetic fields act in the same direction so they will add up

net magnetic field = [ (4 I₀ / r) + (2 I₀ / 3r) ] x 10⁻⁷

= (14 I₀ / 3r ) x 10⁻⁷

Magnetic field at point B = (14 I₀ / 3r ) x 10⁻⁷

Ratio of field at A and B

= 3 / 7 . Ans

3 0

4 years ago

Kyle, a 23-year-old-male, feels as if he is always on the “edge of his seat,” as if something is going to happen. He also has pr

Elden [556K]

Based on the information given, it can be posited that Kyle has a general anxiety disorder.

Generalized Anxiety Disorder is a disorder that is characterized by persistent and excessive worry about different things. People with the disorder may anticipate disaster and are concerned about money, health, family, or other issues.

Some of the effective ways of treatment are spending more time with family and friends, doing regular exercises , enough sleeping, etc.

Learn more about disorder on:

brainly.com/question/25771019

8 0

3 years ago

It takes 130 J of work to compress a certain spring 0.10m. (a) What is the force constant of this spring? (b) To compress the sp

Ede4ka [16]

Explanation:

Given that,

Work done to stretch the spring, W = 130 J

Distance, x = 0.1 m

(a) We know that work done in stretching the spring is as follows :

$W=\dfrac{1}{2}kx^2\\\\k=\dfrac{2W}{x^2}\\\\k=\dfrac{2\times 130}{(0.1)^2}\\\\k=26000\ N/m$

(b) If additional distance is 0.1 m i.e. x = 0.1 + 0.1 = 0.2 m

So,

$W=\dfrac{1}{2}kx^2\\\\W=\dfrac{1}{2}\times 26000\times 0.2^2\\\\W=520\ J$

So, the new work is more than 130 J.

6 0

3 years ago

a body starts from rest and accelerates uniformly at 5ms‐2. Calculate the time taken by the body to cover a distance of 1km​

a body starts from rest and accelerates uniformly at 5ms‐2. Calculate the time taken by the body to cover a distance of 1km