Answer:
![F_x=208.25\ N](https://tex.z-dn.net/?f=F_x%3D208.25%5C%20N)
Explanation:
Given that,
Mass of a crate is 22 kg
It moved up along the 15 degrees incline without tipping.
We need to find the corresponding magnitude of force P. The force P is acting in horizontal direction.
It means that the horizontal component of force is given by :
![F_x=F\cos\theta\\\\F_x=mg\cos\theta\\\\F_x=22\times 9.8\times \cos(15)\\\\F_x=208.25\ N](https://tex.z-dn.net/?f=F_x%3DF%5Ccos%5Ctheta%5C%5C%5C%5CF_x%3Dmg%5Ccos%5Ctheta%5C%5C%5C%5CF_x%3D22%5Ctimes%209.8%5Ctimes%20%5Ccos%2815%29%5C%5C%5C%5CF_x%3D208.25%5C%20N)
So, the horizontal component of force is 208.25 N.
It depends how large the object is. But, if it is 2 by 4, most likely the wood sieges more than the glass.
Hope this helps.
Answer:
The first graph is showing the constant acceleration (1 m/s)
Explanation:
The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4
The last graph is showing constant velocity therefore there is no acceleration (a = 0)