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2 years ago

Please help!! what is the compound of Sr(NO2)2

Chemistry

2 answers:

aksik [14]2 years ago

7 0

Answer:

Anhydrous strontium nitrite

Explanation:

Anhydrous strontium nitrite, Sr(NO2)2, has the CAS number of 13780-06-8 and occurs as yellow-white crystals. It is very hygroscopic. Its density is 2.23 g/cm3 and it decomposes at >650°C to form nitrogen oxides and SrO.

Hope it helps!

valentinak56 [21]2 years ago

4 0

Answer:

I think this is probably the answer you are looking for.

Explanation:

https://youtu.be/PY431ZC5uDc

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Answer: The concentrations of $Cl_2$ at equilibrium is 0.023 M

Explanation:

Moles of $Cl_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol$

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The given balanced equilibrium reaction is,

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

Initial conc. 0.14 M 0 M 0M

At eqm. conc. (0.14-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}$

Now put all the given values in this expression, we get :

$4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}$

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x = 0.023 M

Thus, the concentrations of $Cl_2$ at equilibrium is 0.023 M

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3 years ago

Please help!! what is the compound of Sr(NO2)2​

Please help!! what is the compound of Sr(NO2)2