Explanation:
It is given that,
A planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average orbit radius of Mercury.
Mass of the Sun, 
Radius of Mercury's orbit, 
Radius of discovered planet, 

Let T is the orbital period of such a planet. Using Kepler's third law of planetary motion as :




T = 4135214.625 s
or
T = 47.86 days
So, the orbital period of such a planet is 47.86 days. Hence, this is the required solution.
Answer:
Pressure of woman will be 
Pressure of the elephant will be 
Explanation:
We have given that mass of the woman m = 80 kg
Acceleration due to gravity 
Diameter of shoes = 1 cm =0.01 m
So radius 
So area 
We know that force is given F = mg
So 
Now we know that pressure is given by 
Now mass of elephant m = 5500 kg
So force of elephant = 5500×9.8 = 53900 N
Diameter = 20 cm
So radius r = 10 cm
So area will be 
So pressure will be 
<span>A light-year is the total distance that light can travel in 1 year.
Since, We know the speed of light (c) in vacuum= 299792458 metres per second
And, there are 365.25 days in an year, or t= (365.25*24*60*60) seconds
Hence a light-year (d)=c*t
=299792458Ă—365.25Ă—24Ă—60Ă—60 metres
=9,460,730,472,580,800 metres
â‰9.46073Ă—10^15 metres</span>
Answer:
weakens by 64 times
Explanation:
According to universal law of gravitation the force between two bodies is inversely proportional to square of their distance between them that F is inversely proportional to
So if we increase the the distance between two planets by 8 times then the the mutual attraction between will be decrease by
times