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r-ruslan [8.4K]
3 years ago
9

What is magnetic resonance ???​

Physics
2 answers:
Lemur [1.5K]3 years ago
7 0

Answer:

feu vkdu qtg

gi.rls joi.n for study here i am also a girl here we study girl is allowed here boy are not allowed here we only study so co.me for study in me.et.ing gir.ls co.me for study here its boys disturb me.eting so boys not allowed girls is allowed i am also a girl its a safe me.et.ing

MrRa [10]3 years ago
4 0

Answer:

haajajjsjajajajaaaiiajaka

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creativ13 [48]
They protested by marching in the streets.
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3 years ago
DEFINE the term free fall
PtichkaEL [24]

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when you get to fall for free

Explanation:

4 0
3 years ago
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A 0.2 kg hockey park is sliding along the eyes with an initial velocity of -10 m/s when a player strikes it with his stick, caus
babunello [35]

Answer:

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

Explanation:

The Impulse Theorem states that the impulse experimented by the hockey park is equal to the vectorial change in its linear momentum, that is:

I = m\cdot (\vec{v}_{2} - \vec{v_{1}}) (1)

Where:

I - Impulse, in kilogram-meters per second.

m - Mass, in kilograms.

\vec{v_{1}} - Initial velocity of the hockey park, in meters per second.

\vec{v_{2}} - Final velocity of the hockey park, in meters per second.

If we know that m = 0.2\,kg, \vec{v}_{1} = -10\,\hat{i}\,\left[\frac{m}{s}\right] and \vec {v_{2}} = 25\,\hat{i}\,\left[\frac{m}{s} \right], then the impulse applied by the stick to the park is approximately:

I = (0.2\,kg)\cdot \left(35\,\hat{i}\right)\,\left[\frac{m}{s} \right]

I = 7\,\hat{i}\,\left[\frac{kg\cdot m}{s} \right]

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

8 0
3 years ago
A model rocket is launched directly upward at a speed of 16 meters per second from a height of 2 meters. The function f(t)=−4.9t
Crank

Answer:

Hmax=15.06 meters

Explanation:The question ask for the maximum value of the function f(t) which can be find by find the maxima of the function

The maxima of the function occurs when the slope is zero. i.e.

\frac{df}{dt} =0\\\frac{df}{dt} =\frac{d}{dt} (-4.9t^2+16t+2)\\\frac{df}{dt} =-4.9*2t+16\\-9.8t+16=0\\t=16/9.8\\t=1.63 secs

Hence the maxima occurs at t=1.63 seconds

The maximum value of f is

f(1.63)=-4.9(1.63^2)+16(1.63)+2\\f(1.63)=15.06\\

hence maximum height is found to be

Hmax=15.06 meters

8 0
3 years ago
Object A experiences an attractive force of 50 N when it comes close to Object B. If Object A is positively charged, what can yo
denis23 [38]
It is B since they are traveling at the same speed one is positive so the other had to be negative hope this helps;)))))
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