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Nana76 [90]
3 years ago
11

If a bat hits a ball with a 1000-N force, what force does the ball exert on the bat?

Physics
2 answers:
Masteriza [31]3 years ago
7 0

Answer: The ball will exert 1000 N of force in opposite direction on the bat.

Explanation:

We are given a bat which hits the ball with a force of 1000 N and we need to find the force which the ball exerts on the bat. This phenomena is very well explained by Newton's third law which states that every action has an equal and opposite reaction.

This means that the reaction force will always have an action force which is equal in magnitude.

Hence, the ball exerts an equal magnitude of force on bat which the bat exerts on ball but the force will be acted on in the opposite direction.

So, the ball will exert 1000 N of force in opposite direction on the bat.

scoundrel [369]3 years ago
4 0
Same magnitude (1000N) and opposite direction 
you may also answer -1000 N
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When the force acting on the body equal to acceleration?
topjm [15]

Answer:

Acceleration and velocity Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate, i.e., to change its velocity, at a constant rate. In the simplest case, a force applied to an object at rest causes it to accelerate in the direction of the force.

5 0
2 years ago
Two concentric circular loops of radii b and 2b, made of the same type of wire, lie in the plane of the page, as shown below. Th
sweet-ann [11.9K]

Answer:

a. R2b = R/4

Explanation:

The total resistance of a metallic wire is given by the following formula:

R = ρL/A

where,

R = Resistance of Wire

ρ = Resistivity of the material of wire

L = Length of Wire

A = Area of Wire = πr²

Therefore,

R = ρL/πr²

for the 1st wire,

radius = r = b

Therefore,

R = ρL/πb²   ----------- equation 1

Now, for the second wire,

r = 2b

Therefore,

R2b = ρL/π(2b)²

R2b = ρL/πb²4

using equation 1:

R2b = R/4

therefore, correct option is:

<u>a. R2b = R/4</u>

8 0
3 years ago
A 10kg box is sliding at 50m/s. Find the momentum
MAXImum [283]

Answer:

The momentum of the ball is 500 kg·m/s

Explanation:

The momentum is given by Mass × Velocity

The given parameters are;

The mass of the box = 10 kg

The velocity by which the box is sliding = 50 m/s

Therefore, the momentum of the ball is given as follows;

The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s

The momentum of the ball = 500 kg·m/s

5 0
3 years ago
A 220 g mass is on a frictionless horizontal surface at the end of a spring that has force constant of 7.0
Talja [164]

The concept of conservation of energy and harmonic motion allows to find the result for the power where the kinetic and potential energy are equal is:

        x = 0.135 cm

Given parameters

  • The mass m = 220 g = 0.220 kg
  • The spring cosntnate3 k = 7.0 N / m
  • Initial displacement A = 5.2 cm = 5.2 10-2 m

To find

  • The position where the kinetic and potential energy are equal

 

A simple harmonic movement is a movement where the restoring force is proportional to the displacement, the result of this movement is described by the expression.

          x = A cos wt + fi

          w² = \frac{k}{m}

Where x is the displacement from the equilibrium position, A the initial amplitude of the system, w the angular velocity t the time, fi a phase constant determined by the initial conditions, k the spring constant and m the mass.

The speed is defined by the variation of the position with respect to time.

       v = \frac{dx}{dt}

let's evaluate

       v = - A w sin (wt + Ф)

Since the body releases for a time t = 0 the velocity is zero, therefore the expression remains.

       0 = - A w sin Ф

For the equality to be correct, the sine function must be zero, this implies that the phase constant is zero

        x = A cos wt

Let's find the point where the kinetic and potential energy are equal.

        K = U

        ½ m v² = m g x

       

we substitute

        ½ A² w² sin² wt = g A cos wt

        sin² wt = \frac{2g}{A}  cos wt

let's calculate

      w = \sqrt{\frac{7}{0.220} }  

      w = 5.64 rad / s

      sin² 5.64t = 2 9.8 / 0.052 cos 5.64t

      sin² 5.64t = 376.92 cos 5.64 t

      1 - cos² 5.64t = 376.92 cos 5.64t

      cos² 5.64t -376.92 cos564t -1 = 0

we make the change of variable

       x = cos 5.64t

      x²- 376.92 x - 1 = 0

      x = 0.026

      cos 5.64t = 0.026

   

Let's find the displacement for this time

       x = 5.2 10-2 0.026

       x = 1.35 10-3 m

In conclusion Using the concepts of conservation of energy and harmonic motion we can find the result for the could where the kientic and potential enegies are equal is:

        x = 0.135 cm

Learn more here: brainly.com/question/15707891

8 0
3 years ago
5. The net external force on a rock of mass 4.2 kg is 8.0 N forward. Find the acceleration of the rock.
andreev551 [17]

Answer:

1.904

Explanation:

F= ma

8 = 4.2 a

a = 8/4.2

a = 1.904

6 0
2 years ago
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