<span>my first part it like that as we all know that flux density is the charge per unt area here charge is 60uc so divide 60uc by (4*pi*r2) we get D= 7.06*10^-5 c/m2
</span><span>NOW given is portion with r=26cm theta= 0 to pi/2 and phi = 0 to pi/2
calculate required region area with formula =double integral(r^2sintheta dtheta dphi)
we get =.106m^2 now multiply D*Required region we get 7.5uc</span>
Answer:
Velocity is a vector quantity. It has both, magnitude and direction. Velocity is the rate of change in the position of a body with respect to a frame of reference. One component is the magnitude of velocity which is speed. The other one is its direction.
Explanation:
Speed is a scalar quantity.
Velocity is a vector quantity.
There are two types of quantities:
1. Scalar quantity:
A scalar quantity is a quantity which is described by its magnitude alone.
2. Vector Quantity:
A vector quantity is a quantity which is described completely by both, its magnitude and direction.
I don't know
but a single substance is any sample of the known elements found in the periodic table of elements elements are made up of atoms of the same kind and cannot be decomposed by any chemical means into any other simpler elements.
Answer:
Car A is 1.8-1.2= 0.6 times faster than car B
So the distance between them is changing 0.6 times faster.
Explanation:
Car A is traveling north at 90km/hr and 0.3 km away from intersection point.
Car b is traveling west at 80km/hr and 0.4 km away from the intersection point.
The time it will take to get to intersection point by those two cars is how fast it is changing.
For car A
Time = distance/speed
Time = 0.3/90
Time = 3.333*10^-3
Time = 3.333*10^-3 hrs
Converting to seconds
(3.333*10^-3)*360= 1.199998
Approximately 1.2 seconds
For car B
Time = distance/time
Time= 0.4/80
Time = 5*10^-3
Time= 5*10^-3 hrs
Converting to seconds
(5*10^-3)*360= 1.8 seconds
Comparing the two times,
Car A is 1.8-1.2= 0.6 times faster than car B
The radius of its orbit = 8.27 x 10¹³ m
<h3>Further explanation</h3>
Given
mass Jupiter=1.9 x 10²⁷ kg
T = 16.9 days=1.46 x 10⁶ s
Required
the radius =r
Solution
To hold the moon in its orbit, the gravitational force between two objects (jupiter and moon) will be equal to the centripetal force
G = 6.67 x 10⁻¹¹ N/m²kg²
Input the value :