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3 years ago

Desperate for help! please!!!!!!!!

Physics

1 answer:

lys-0071 [83]3 years ago

8 0

$0.4029 \mathrm{m} / \mathrm{s}^{2}$ is the acceleration of the box.

Explanation:

Given data:

Mass of the box = 3.74 kg

Flat friction-less ground is pulled forward by a 4.20 N force at a 50.0 degree angle and pulled back by a 2.25 N force at a 122 degree angle.

First, we need to find the net horizontal force acting on the box. With the given data, the equation can be formed as below. Net horizontal force acting on the box (F) is given by

$F=\left(4.20 \times \cos 50^{\circ}\right)+\left(2.25 \times \cos 122^{\circ}\right)$

$F=(4.20 \times 0.64278)+(2.25 \times-0.5299)$

F = 2.699676 – 1.192275 = 1.507 N

Next, find acceleration of the box using Newton's second law of motion. This states that the link between mass (m) of an objects and the force (F) required to accelerate it. The equation can be given as

$F=m \times acceleration\ (a)$

$\text {acceleration }(a)=\frac{F}{m}=\frac{1.507}{3.74}=0.4029 \mathrm{m} / \mathrm{s}^{2}$

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Answer:

Part a)

$t = 5.1 s$

Part b)

$x = 176.7 m$

Explanation:

Initial speed of the launch is given as

$v_i = 40 m/s$

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Now the two components of the velocity

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similarly we have

$v_y = v_i sin30$

$v_y = 20 m/s$

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Now to find the time of flight we will have

$\Delta y = v_y t + \frac{1}{2}at^2$

$-25 = 20 t -\frac{1}{2}(9.81)t^2$

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Part b)

Distance at which the ball will land is given as

$x = v_x t$

$x = 34.6 (5.1)$

$x = 176.7 m$

Part c)

Since x direction there is no acceleration so it will move with uniform speed while in y direction it will accelerate due to gravity

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A wedge is a machine and it is used for separating bodies.

<h3 /><h3>The Wedge as a Machine</h3>

The wedge is a combination of two inclined planes. When the wedge is driven into a body by an effort force, a much larger force will be exerted to each side by the wedge surfaces.

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2 years ago

Two drums of the same size and same height are taken.

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Answer:

i) The pressure acting on the base of B will be half the pressure acting on the base of A

ii) The pressure acting on the base of B will be the same as the pressure acting on the base of A

iii) The pressure on the base of drum A will be slightly less than the pressure on the base of drum B

Explanation:

The pressure acting on the base of the drum, P = h·ρ·g

Where;

h = The level of the liquid in the drum

$h_{max}$ = The height of the drums

ρ = The density of the liquid in the drum

g = The acceleration due to gravity ≈ 9.81 m/s²

i) If A is completely filled, we have $h_A$ = $h_{max}$

Therefore, $P_A$ = $h_{max}$ × $\rho_{liquid}$ ×g

If B is half filled, we have, $h_B$ = (1/2)· $h_{max}$

$P_B$ = (1/2) × $h_{max}$ × $\rho_{liquid}$ ×g

Therefore, $P_B$ = (1/2) × $P_A$

The pressure acting on the base of B will be half the pressure acting on the base of A

ii) If both A and B are each filled with water (the same liquid), then the pressure on their bases will be $P_A$ = $h_{max}$ × $\rho_{water}$ ×g = $P_B$ , the same, given that the acceleration due to gravity, g, is constant and the same in Nepal and India

iii) If A is filled with water, and B is filled with salty water, we have that, the density of salty water is slightly higher than water, therefore, we get;

$P_A$ = $h_{max}$ × $\rho_{water}$ ×g < $P_B$ =

The pressure on the base of drum A will be less than the pressure on the base of drum B.

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