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Artemon [7]
3 years ago
11

Explain three ways in which a campfire transfers energy to

Physics
1 answer:
barxatty [35]3 years ago
5 0
Hello I am the guy to be mad at.
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PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!
konstantin123 [22]
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3 0 0 k m
7 0
3 years ago
Read 2 more answers
ILI
Nikolay [14]

The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.

<u>Explanation:</u>

As it is known that the kinetic energy is defined as the energy exhibited by the moving objects. So the kinetic energy is equal to the product of mass and square of the velocity attained by the car. Thus,

                  \text {Kinetic energy}=\frac{1}{2} m v^{2}

So the initial kinetic energy will be the energy exerted by the car at the initial state when the initial velocity is zero. Thus the initial kinetic energy will be zero.  

The final kinetic energy is

\text {Kinetic energy}=\frac{1}{2} m v^{2}=\frac{1}{2} \times 600 \times 5 \times 5 = 7500 J

As the work done is the energy required to start the car from zero velocity to 5 m/s velocity.  

                       Work done = Final Kinetic energy - Initial Kinetic energy

Thus the work utilized for moving the car is  

                         Work done = 7500 J - 0 J = 7500 J

Thus, the initial kinetic energy of the car is zero, the final kinetic energy is 7500 J and the work utilized by the car is also 7500 J.

7 0
3 years ago
Voidddddddddddddddddddddddd<br>​
bogdanovich [222]

Answer: understandable have a nice day

Explanation:

5 0
3 years ago
The telescope that allowed astronomers to discover most of the planets found with the transit method was called:.
kvasek [131]

Answer:This quest took a huge leap forward in 2000 when Hubble studied the exoplanet HD 209458 b, the first extrasolar planet known to make “transits” across the face of its star. Hubble became the first telescope to directly detect an exoplanet's atmosphere and survey its makeup.

Explanation:

4 0
2 years ago
How much work is required to lift a 2 kilogram mass to a height of 10 meters
Semmy [17]

Given mass = 2kg, height = 10m,g = 9.8.


We know that Work done W = FD


= > W = (mg)(D)


= > W = (2 * 9.8)(10)


= > W = 196 Joules.


Hope this helps!

4 0
3 years ago
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