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wolverine [178]
3 years ago
9

Which of the following settings best create fear or anxiety?

Physics
2 answers:
MAVERICK [17]3 years ago
6 0

Answer:

option d) is correct

Explanation:

option d) is correct

castle ruins is the setting best create fear or anxiety because ruining castle means that there is war going on.

War is the condition where every one is tense and this condition creates fear and anxiety in the people facing the scenario of fear.

so, the best option is castle ruins.

Papessa [141]3 years ago
3 0
"Castle ruins" is the one settings among the following choices given in the question that <span>create fear or anxiety. The correct option among all the options that are given in the question is the last option or the fourth option. I hope that this is the answer that you were looking for and the answer has actually come to your help.</span>
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What will be the force if the particle's charge is tripled and the electric field strength is halved? Give your answer in terms
Alexus [3.1K]

Answer:

1.5F

Explanation:

Using

E= F/q

Where F= force

E= electric field

q=charge

F= Eq

So if qis tripled and E is halved we have

F= (E/2)3q

F= 1.5Eq=>> 1.5F

4 0
3 years ago
Red shift data shows that galaxies are O expanding O shrinking O moving away O moving closer
Anon25 [30]

Answer:

Should be moving away

Explanation:

Red is a longer wavelength therefore further away. Wavelength is stretched out more and on the red end. I hope this is right. I decided to research and answer since you didn’t have other answers. Are you taking this on edg? I hope I helped!

7 0
3 years ago
I need help with this problem.
tamaranim1 [39]

Answer:

Explanation:

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7 0
3 years ago
A particle with charge 3.01 µC on the negative x axis and a second particle with charge 6.02 µC on the positive x axis are each
ra1l [238]

Answer:

The third particle should be at 0.0743 m from the origin on the negative x-axis.

Explanation:

Let's assume that the third charge is on the negative x-axis. So we have:

E_{1}+E_{3}-E_{2}=0

We know that the electric field is:

E=k\frac{q}{r^{2}}

Where:

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  • r is the distance from the charge to the point

So, we have:

k\frac{q_{1}}{r_{1}^{2}}+k\frac{q_{3}}{r_{3}^{2}}-k\frac{q_{2}}{r_{2}^{2}}=0

Let's solve it for r(3).

\frac{3.01}{0.0429^{2}}+\frac{9.03}{r_{3}^{2}}-\frac{6.02}{0.0429^{2}}=0

r_{3}=0.0743\:  

Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.

I hope it helps you!

 

3 0
3 years ago
The force that causes an impulse and a force that causes a change in momentum are?
Aleks [24]
I don't understand the question but impulse and momentum is the same. So maybe is the force same too
3 0
2 years ago
Read 2 more answers
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