Answer:
Preparation. Copper(I) iodide can be prepared by heating iodine and copper in concentrated hydriodic acid, HI. In the laboratory however, copper(I) iodide is prepared by simply mixing an aqueous solution of potassium iodide and a soluble copper(II) salt such copper sulfate.
2C5H12 + 16O2 —> 10CO2 + 12H2O
2•5=10 C 10=1•10
2•12=24 H 24=2•12
16•2=32 O 32=(10•2)+(1•12)
=20+12
Answer:
3.25 mol CO₂
Explanation:
Step 1: Write the balanced equation
C(s) + O₂(g) ⇒ CO₂(g)
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to CO₂ is 1:1.
Step 3: Calculate the number of moles of CO₂ produced from 3.25 moles of O₂
We will use the previously established molar ratio.
3.25 mol O₂ × 1 mol CO₂/ 1 mol O₂ = 3.25 mol CO₂