We can use the ideal gas law equation to solve for the number of moles present
PV = nRT
P - pressure - 107 kPa
V - 39.0 x 10⁻⁶ m³
n - number of moles
R - 8.314 Jmol⁻¹K⁻¹
T - temperature in K - 27 °C + 273 = 300 K
Substituting these values into the equation
107 000 Pa x 39.0 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K
n = 1.67 x 10⁻³ mol
This process is called fusion.
To calculate the molecular formula, convert the mass ratio into molar ratio as follows:
mass ratio of O:C=2:1
molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus, number of moles can be calculated as follows:
n=\frac{m}{M}
calculating ratio,
O:C=\frac{2 g}{16 g/mol}:\frac{1 g}{12 g/mol}=\frac{1}{8}:\frac{1}{12}=12:8=3:2
thus, molecular formula will be C_{2}O_{3}
When a mixture of 10 moles of SO2 and 15 moles of O2 was passed over a catalyst, 10 moles of SO3 was formed.
Answer:
50g of CaCO3=1. 5∗(6. 022∗1023)=9. 035∗1023 oxygen atoms