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Delvig [45]
3 years ago
15

What did Rutherford’s gold foil experiment indicate?

Chemistry
1 answer:
Klio2033 [76]3 years ago
4 0
The answer would be D. 
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How many moles of KBr are present in 8.96 x 10^21
Gelneren [198K]

Answer:

0.015 moles

Explanation:

  • One mole of a compound contains molecules equivalent to the Avogadro's constant, 6.022 × 10^23.
  • That is, 1 mole of a compound will have 6.022 × 10^23 molecules.

In our case, We are given 8.96 x 10^21 molecules of KBr

We need to find the number of moles in 8.96 x 10^21 molecules

1 mole of KBr = 6.022 × 10^23 molecules.

8.96 x 10^21 molecules = ?

Therefore;

(1 × 8.96 x 10^21 molecules ) ÷ 6.022 × 10^23 molecules.

 = 1.488 × 10^-2 moles

 = 0.01488 moles

= 0.015 moles

6 0
3 years ago
Help asap, timed assingment
Genrish500 [490]

Answer:

concentration of mitochondria

Explanation:

6 0
3 years ago
Calculate the number of oxygen atoms and its mass in 50g of CaCo3<br>​
xz_007 [3.2K]

The number of oxygen atoms = 3

Mass = 24 g

<h3>Further explanation</h3>

The formula of a compound shows the composition of the constituent elements

CaCO₃ is composed of 3 types of elements, namely Ca, C and O

The amounts of each of these elements in the compound CaCO₃:

  • Ca = 1
  • C = 1
  • O = 3

So the number of oxygen atoms = 3

mass of Oxygen :

\tt mass~O=\dfrac{3\times Ar~O}{MW~CaCO_3}\times mass~CaCO_3\\\\mass~O=\dfrac{3\times 16}{100}\times 50=24~g

5 0
2 years ago
The balanced equation below shows the products that are formed when butane (C4H10) is combusted. 2C4H10 + 13O2 mc009-1.jpg 8CO2
Verizon [17]
The correct answer would be option 1. The mole ratio of butane to carbon dioxide is 1:4. Looking at the balanced chemical reaction, we see that we need 2 moles of butane to produce 8 moles of carbon dioxide. So, it is 2:8. Simplifying this by dividing both to 2, we have 1:4.
6 0
3 years ago
Read 2 more answers
You have 1.88 moles of NaOH and an excess of H2SO4. How many grams of H2O will be produced?
KATRIN_1 [288]

Answer:

2 NaOH + H2SO4 2 H2O + Na2SO4

How many grams of sodium sulfate will be formed if you start with 200.0

grams of sodium hydroxide and you have an excess of sulfuric acid?

355.3 grams of Na2SO4

200.0 g NaOH 1 mol NaOH 1 mol Na2SO4 142.1 g Na2SO4

40.00 g NaOH 2 mol NaOH 1 mol Na2SO4

= 355.3 g

Explanation:

3 0
2 years ago
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