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Delvig [45]
3 years ago
15

What did Rutherford’s gold foil experiment indicate?

Chemistry
1 answer:
Klio2033 [76]3 years ago
4 0
The answer would be D. 
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Explain why lime is added to lakes. Refer to the problem that exists and what lime does to the lakes.
aalyn [17]

Explanation:

Lime is added to lower the acidity of lakes when pH levels go too low.

Acidic environment is harmful to aquatic ecosystems. Acidity causes some minerals, such as phosphorus and calcium, in the water to become unavailable to aquatic organisms like plants and fishes ( This means the water hardness is reduced). The low nutrients cause stress and death in the aquatic environment lowering biodiversity.  Applying lime raises the pH to neutral levels and improves the health of the aquatic life in the lake. This also improves economic activities in the lake like fishing.

Learn More:

For more on acidicity of lakes check out;

brainly.com/question/3612253

brainly.com/question/3612253

#LearnWithBrainly

4 0
3 years ago
When the disk of the moon masks the disk of the sun, it creates a _________ eclipse.
Dvinal [7]
When the disk of the moon mask the the disk of the sun,it creates a (solar) eclipse.
4 0
3 years ago
Read 2 more answers
A 30.0g sample of O2 at standard temperature and pressure (STP) would occupy what volume in liters
Murrr4er [49]

Answer:

Explanation:

A 30.0g sample of O2 at standard temperature and pressure (STP) would occupy what volume in liters

PV =nRT

at STP  P= 1atm. T= 273 K

n is the number of moles.  O2 has a molar mass of 32.

30 gm of O2 is 30/32= 0.94 =n

PV = nRT

at STP: P= 1 atm, T=273 K, R is always 0.082 for P in atm and T in K

SO

1 X V = 0.94 X 0.082 X 273

using high school freshman algebra,

V= 0.94 X 0.082 X 273 = 21L

using high school algebra I,

V=

6 0
2 years ago
When energy is transferred from the air to the water, what happens to most of the energy?
Norma-Jean [14]
Most of the energy travels trough the water
3 0
3 years ago
When 1.025 g of naphthalene (c10h8) burns in a bomb calorimeter, the temperature rises from 24.25°c to 32.33°c. find δerxn for t
Goryan [66]

Answer : The \Delta E for the combustion of naphthalene is 5161.25KJ/mole

Solution : Given,

Mass of naphthalene = 1.025 g

Initial temperature = 24.25^oC

Final temperature = 32.33^oC

Specific heat capacity of calorimeter = 5.11KJ/^oC

Molar mass of naphthalene = 128 g/mole

First, we have to calculate the heat absorbed, q

Formula used :

q=c\times \Delta T=c\times (T_{final}-T_{initial})

Now put all the given values in this formula, we get

q=(5.11KJ/^oC)\times (32.33^oCT-24.25^oC)=41.29KJ

Now we have to calculate the moles of naphthalene.

Moles of C_{10}H_{8} = \frac{\text{ Mass of }C_{10}H_{8}}{\text{ Molar mass of }C_{10}H_{8}}=\frac{1.025g}{128g/mole}=0.0080moles

Now we have to calculate the \Delta E for combustion of naphthalene.

\Delta E=\frac{q}{n}

where,

q = heat absorbed

n = number of moles

Now put all the values in this formula, we get

\Delta E=\frac{41.29KJ}{0.0080moles}=5161.25KJ/mole

Therefore, the \Delta E for the combustion of naphthalene is 5161.25KJ/mole

6 0
3 years ago
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