Answer:
66.0 mL HClO3
Explanation:
M1V1 = M2V2
M1 = 0.100 M HClO3
V1 = ?
M2 = 0.165 M KOH
V2 = 40.0 mL KOH
Solve for V1 --> V1 = M2V2/M1
V1 = (0.165 M)(40.0 mL) / (0.100 M) = 66.0 mL HClO3
At first I thought it was c but then I checked And it’s either B or A? I’m thinking mostly A but good luck
There are a lot of molecules in H2O.<span />
Answer:
d = 0.9 g/L
Explanation:
Given data:
Number of moles = 1 mol
Volume = 24.2 L
Temperature = 298 K
Pressure = 101.3 Kpa (101.3/101 = 1 atm)
Density of sample = ?
Solution:
PV = nRT (1)
n = number of moles
number of moles = mass/molar mass
n = m/M
Now we will put the n= m/M in equation 1.
PV = m/M RT (2)
d = m/v
PM = m/v RT ( by rearranging the equation 2)
PM = dRT
d = PM/RT
The molar mass of neon is = 20.1798 g/mol
d = 1 atm × 20.1798 g/mol / 0.0821 atm. L/mol.K × 273K
d = 20.1798 g/22.413 L
d = 0.9 g/L