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Viktor [21]
3 years ago
9

ANYONE PLEASE HELP ME WITH MY MATH HOMEWORK I REALLY NEED THE ANSWER RIGHT NOW BECAUSE I HAVE TO PASS THIS LATER I HOPE Y'ALL CA

N HELP ME:(
I'LL MARK YOU AS THE BRAINLIEST!

IT'S JUST TWO QUESTIONS:(​

Mathematics
2 answers:
ch4aika [34]3 years ago
6 0
1 is 7
and
2 is 1
i hope this is right i haven’t done this math in a while
Sonja [21]3 years ago
4 0

Answer:

should be the correct brainliest answer

Step-by-step explanation:

1=0

2=1

anything times zero is 0

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Leslie invests $2500 in a savings account for 10 years. The account accrues interest at a rate
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Answer:

You make $32,000 a year and want to save 10% of your income every year. How much should you put into savings every month?

$32$,000 x 0.10 = 3,200

You want to save $3200 a year.

You should be saving $266.67 a month or $133.33 a paycheck if you are paid

Step-by-step explanation:

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3 years ago
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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

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3 years ago
How many 3 card hands are possible with a 36​-card ​deck?
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is 2

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3 years ago
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f(2) = 0.42 + 0.20(4.1-1)
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0.80 + 1.04 = 1.84 last choice
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3 years ago
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