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2 years ago

How many C8H18 particles would be in 12.6 moles of octane (C8H18)?

1 answer:

5 0

Taking into account the definition of Avogadro's number, 7.59×10²⁴ particles of C₈H₁₈ would be in 12.6 moles of octane.

<h3>Definition of Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Amount of C₈H₁₈ particles</h3>

Then you can apply the following rule of three: If by definition of Avogadro's number 1 mole of C₈H₁₈ contains 6.023×10²³ particles, 12.6 moles of the compound contains how many particles?

amount of particles of C₈H₁₈= (6.023×10²³ particles × 12.6 mole)÷ 1 mole

<u><em>amount of particles of C₈H₁₈= 7.59×10²⁴ particles</em></u>

Finally, 7.59×10²⁴ particles of C₈H₁₈ would be in 12.6 moles of octane.

Learn more about Avogadro's Number:

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Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH

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Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{12 g}{60 g/mol}$

= 0.2 mol

Molarity of acetic acid is calculated as follows.

Density = $\frac{mass}{volume}$

1 g/ml = $\frac{100 g}{volume}$

volume = 100 ml

Hence, molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{0.2 mol}{0.1 L}$

= 2 mol/l

As reaction equation for the given reaction is as follows.

$NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O$

So, moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

$x \times 1 M = 10 mL \times 2 M$ (as 1 L = 1000 ml)

x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.

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3 years ago

4Na + O2 2Na2O

beks73 [17]

4
N
a
+
O
2
→
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By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol
N
a
2
O
should result.
Explanation:
The molecular mass of natrium oxide is
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g
⋅
m
o
l
−
1
. If
5

m
o
l
natrium react, then
5
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m
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l
×
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g
⋅
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=

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