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nirvana33 [79]
2 years ago
10

How many C8H18 particles would be in 12.6 moles of octane (C8H18)?

Chemistry
1 answer:
GuDViN [60]2 years ago
5 0

Taking into account the definition of Avogadro's number, 7.59×10²⁴ particles of C₈H₁₈ would be in 12.6 moles of octane.

<h3>Definition of Avogadro's Number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Amount of C₈H₁₈ particles</h3>

Then you can apply the following rule of three: If by definition of Avogadro's number 1 mole of C₈H₁₈ contains 6.023×10²³ particles, 12.6 moles of the compound contains how many particles?

amount of particles of C₈H₁₈= (6.023×10²³ particles × 12.6 mole)÷ 1 mole

<u><em>amount of particles of C₈H₁₈= 7.59×10²⁴ particles</em></u>

Finally, 7.59×10²⁴ particles of C₈H₁₈ would be in 12.6 moles of octane.

Learn more about Avogadro's Number:

brainly.com/question/11907018?referrer=searchResults

brainly.com/question/1445383?referrer=searchResults

brainly.com/question/1528951?referrer=searchResults

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Explanation:

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%/100wt => grams/100wt => moles => ratio => reduce => emp ratio

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Ratio N:H => 17.9 : 5.9

Reduce mole ratio (divide by smaller mole value) => 17.9/5.9 : 5.9/5.9

=> 3HY:1H empirical ratio => empirical formula NH₃ (ammonia)

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