Where are the answers that apply .. hopes this help :)
Answer:
How to convert volts to electron-volts
How to convert electrical voltage in volts (V) to energy in electron-volts (eV).
You can calculate electron-volts from volts and elementary charge or coulombs, but you can't convert volts to electron-volts since volt and electron-volt units represent different quantities.
Volts to eV calculation with elementary charge
The energy E in electron-volts (eV) is equal to the voltage V in volts (V), times the electric charge Q in elementary charge or proton/electron charge (e):
E(eV) = V(V) × Q(e)
The elementary charge is the electric charge of 1 electron with the e symbol.
So
electronvolt = volt × elementary charge
or
eV = V × e
Example
What is the energy in electron-volts that is consumed in an electrical circuit with voltage supply of 20 volts and charge flow of 40 electron charges?
E = 20V × 40e = 800eV
Volts to eV calculation with coulombs
The energy E in electron-volts (eV) is equal to the voltage V in volts (V), times the electrical charge Q in coulombs (C) divided by 1.602176565×10-19:
E(eV) = V(V) × Q(C) / 1.602176565×10-19
So
electronvolt = volt × coulomb / 1.602176565×10-19
or
eV = V × C / 1.602176565×10-19
Example
What is the energy in electron-volts that is consumed in an electrical circuit with voltage supply of 20 volts and charge flow of 2 coulombs?
E = 20V × 2C / 1.602176565×10-19 = 2.4966×1020eV
Explanation:
Answer:
the stoichiometric coefficient for cobalt is 3
Explanation:
the unbalanced reaction would be
Co(NO₃)₂+ Al → Al(NO₃)₃ + Co
One way to solve is to build a system of linear equations for each element (or group as NO₃) , knowing that the number of atoms of each element is conserved.
For smaller reactions a quick way to solve it can be:
- First the Co as product and as reactant needs to have the same stoichiometric coefficient
- Then the Al as product and as reactant needs to have the same stoichiometric coefficient
- After that we look at the nitrates . There are 2 as reactants and 3 as products . Since the common multiple is 6 then multiply the reactant by 3 and the product by 2.
Finally the balanced equation will be
3 Co(NO₃)₂+ 2 Al → 2 Al(NO₃)₃ + 3 Co
then the stoichiometric coefficient for cobalt is 3
OH- is the ion that increases the concentration of a base
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