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den301095 [7]
2 years ago
6

A 3.8 g sample of sodium hydrogen carbonate is added to a solution of acetic acid weighing 10.8 g. The two substances react, rel

easing carbon dioxide gas to the atmosphere. After the reaction, the contents of the reaction vessel weigh 11.6 g. What is the mass of carbon dioxide released during the reaction
Chemistry
1 answer:
UkoKoshka [18]2 years ago
8 0

Answer:

3.0 g

Explanation:

The <em>total mass </em>at the beginning of the reaction is:

  • 3.8 g + 10.8 g = 14.6 g

Following the law of conservation of mass, this same mass has to be present once the reaction is complete. This means that the mass diference between <em>the contents of the reaction vessel after the reaction and the mass at the beginning of the reaction</em> is the mass of released carbon dioxide:

  • 14.6 g - 11.6 g = 3.0 g
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Which metal cations form a white precipitate with both H2SO4(aq) and Na2S2O4(aq)? 1. Ba2+ 2. Sr2+ 3. Fe2+ 4. Cu2+
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1. Ba2+ 2. Sr2+

Explanation:

When a solution contains the Barium ,Ba²⁺ ion or Strontium, Sr²⁺ ion, they reacts with either H₂SO₄(aq) or Na₂SO₄(aq) to produce a white precipitate of BaSO₄(s) and SrSO₄(s) respectively

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6 0
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Carry out the following operations as if they were calculations of experimental results and express each answer in standard nota
Shalnov [3]

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1. 10.6\; \rm m (one decimal place.)

2.0.79\; \rm g (two decimal places.)

3. 16.5\;\rm cm^2 (three significant figures.)

Explanation:

<h3>1.</h3>

The first and second expressions are additions and subtractions. When adding two numbers, the accuracy of the result is given by the number of decimal places in it. The result should have as many decimal places as the input with the least number of decimal places.

For example, in the first expression:

  • 5.6792\;\rm m has four decimal places.
  • 0.6\; \rm m has only one decimal place.
  • 4.33\; \rm m has two decimal places.

Therefore, the result should be rounded to one decimal place. Note that these units are compatible for addition, since they are all the same. The result should have the same unit (that is: \rm m.)

Therefore:

\rm 5.6792\; m + 0.6\; m + 4.33\; m \approx 10.6\; \rm m. (Rounded to one decimal place.)

<h3>2.</h3>

Similarly:

  • \rm 3.70\; \rm g has two decimal places.
  • 2.9133\; \rm g has four decimal places.

Therefore, the result should be rounded to two decimal places. Its unit should be \rm g (same as the unit of the two inputs.)

\rm 3.70\; g - 2.9133\; g \approx 0.79\; \rm g. (Rounded to two decimal places.)

<h3>3.</h3>

When multiplying two numbers, the accuracy of the result should be based on the number of significant figures in it. The result should have as many significant figures as the input with the least number of significant figures. In this expression:

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Therefore, the result should have only three significant figures.

The unit of the result is supposed to be the product of the units of the input. In this expression, that unit will be \rm cm \cdot cm, which is occasionally written as \rm cm^2.

\rm 4.51 \; cm \times 3.6666 \; cm \approx 16.5\; \rm cm^2. (Rounded to three significant figures.)

7 0
3 years ago
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