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den301095 [7]
3 years ago
6

A 3.8 g sample of sodium hydrogen carbonate is added to a solution of acetic acid weighing 10.8 g. The two substances react, rel

easing carbon dioxide gas to the atmosphere. After the reaction, the contents of the reaction vessel weigh 11.6 g. What is the mass of carbon dioxide released during the reaction
Chemistry
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

3.0 g

Explanation:

The <em>total mass </em>at the beginning of the reaction is:

  • 3.8 g + 10.8 g = 14.6 g

Following the law of conservation of mass, this same mass has to be present once the reaction is complete. This means that the mass diference between <em>the contents of the reaction vessel after the reaction and the mass at the beginning of the reaction</em> is the mass of released carbon dioxide:

  • 14.6 g - 11.6 g = 3.0 g
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Correct answer: 3. Mg^{2+}(aq) + 2 F^{-}(aq) --> MgF_{2}(s)

The given chemical reaction is between ammonium fluoride and magnesium chloride to form magnesium fluoride and ammonium chloride.

The balanced chemical equation representing the reaction will be,

2NH_{4}F (aq) + MgCl_{2}(aq) -->MgF_{2} (s) + 2NH_{4}Cl (aq)

The complete ionic equation for the reaction: All the compounds soluble in water (aqueous) will split into ions, MgF_{2} will not split into ions as it is insoluble in water.

2 NH_{4}^{+}(aq) + 2 F^{-}(aq) + Mg^{2+}(aq) + 2 Cl^{-}(aq) --> MgF_{2}(s) + 2 NH_{4}^{+}(aq) + 2 Cl^{-}(aq)

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For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of
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The given reaction is:

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Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe  = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O;  Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

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Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

 


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