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Maslowich
3 years ago
15

How does the chemical formula for the nitrite ion differ than the chemical formula for the nitrate ion?

Chemistry
1 answer:
olasank [31]3 years ago
7 0
Hope this helps you!

You might be interested in
Balance Na + SO3 = Na2SO3
Orlov [11]
2 Na + SO3 = Na2SO3

Na = 1
SO3 = 1
Na2SO3 = 1

Na = 2
SO3 = 1
Na2SO3 = 1

I hope this helps!!



7 0
3 years ago
Please help me with this.<br><br><br>And show all work as well ASAP!!​
qaws [65]

Answer: The partial pressure of oxygen is 187 torr.

Explanation:

According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.

p_1=x_1p_{total}  

where, x = mole fraction  

p_{total} = total pressure  

x_{oxygen}=\frac{\text {moles of oxygen}}{\text {total moles}},  

x_{oxygen}=\frac{3.0}{12.33}=0.243,  

p_{oxygen}=0.243\times 770torr=187torr  

Thus the partial pressure of oxygen is 187 torr.

6 0
3 years ago
6CO2 + 6H2O → C8H12O6 + 602
maxonik [38]

Answer:

B. One element and one compound

Explanation:

O2 is a diatomic element: "are pure elements that form molecules consisting of two atoms bonded together"

*there are 7 types of diatomic elements

and...

C8H12O6 is a compound

Chemical Compound can be described as  "a chemical substance composed of many identical molecules composed of atoms from more than one element held together by chemical bonds"

8 0
3 years ago
How do you convert between the mass and the number of moles of a substance?
Ksivusya [100]
To convert from grams to moles, you divide the number of grams by the molar mass To convert  from moles to grams, you multiply by the molar mass. You must first calculate the molar mass of the substance
6 0
3 years ago
What is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 ml of solution?
choli [55]

Answer:

M=0.638M

Explanation:

Hello!

In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:

n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol

Then, the liters of solution:

V=325mL*\frac{1L}{1000mL} =0.325L

Finally, the molarity turns out:

M=\frac{0.207mol}{0.325L}\\\\M=0.638M

Best regards!

5 0
3 years ago
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