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Sunny_sXe [5.5K]
2 years ago
10

HELP PLS RIGHT ANSWER GETS BRAINLIEST!!!!

Physics
1 answer:
mr Goodwill [35]2 years ago
8 0

Answer:

<em><u>♧</u></em><em><u> </u></em><em><u>Write</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>abbreviation</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>metric</u></em><em><u> </u></em><em><u>unit</u></em><em><u>.</u></em>

  1. kg
  2. m
  3. g
  4. mL
  5. mm
  6. L
  7. km
  8. cm
  9. mg

<em><u>♧</u></em><em><u> </u></em><em><u>Try</u></em><em><u> </u></em><em><u>these</u></em><em><u> </u></em><em><u>conversions</u></em><em><u>,</u></em><em><u> </u></em><em><u>using</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>ladder</u></em><em><u> </u></em><em><u>method</u></em><em><u>.</u></em>

  1. 2 g
  2. 104000 m
  3. 4.8 m
  4. 5600 g
  5. 0.8 cm
  6. 5000 mL
  7. 0.198 kg
  8. 0.075 L
  9. 0.5 m
  10. 560 cm
  11. 160 mm
  12. 2.5 km
  13. 65000 mg
  14. 63 mm
  15. 0.12 g

<em><u>♧</u></em><em><u> </u></em><em><u>Compare</u></em><em><u> </u></em><em><u>using</u></em><em><u> </u></em><em><u><</u></em><em><u>,</u></em><em><u> </u></em><em><u>></u></em><em><u>,</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>=</u></em><em><u>.</u></em>

16. <

17. >

18. =

19. =

20. <

21. >

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How much heat will be needed to warm 187 grams of water from 10 0C to 90 0C?
kvv77 [185]
<h3>Hello there!</h3>

Here, you are looking for the amount of heat put in for water, at a mass of 187 grams, to change by 80 degrees.

The equation commonly accepted to find the answer to questions like these is the specific heat formula.

The equation is Q = mc∆T, where Q is the amount of energy put in to raise the temperature by a certain amount, m is the mass, c is the specific heat capacity, and ΔT is the amount of temperature change.

The information given:

m = 187 grams

c = specific heat capacity of water, or in this case 1 calorie, or 4.184 joules (which is what we will be using)

ΔT = 80 degrees

Now just plug everything in to solve.

Q = 187 * 4.184 * 80

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So you have your answer: 62592.64 joules.

Hope this helped!

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pychu [463]
By definition we have that the final speed is:
 Vf² = Vo² + 2 * a * d
 Where,
 Vo: Final speed
 a: acceleration
 d: distance.
 We cleared this expression the acceleration:
 a = (Vf²-Vo²) / (2 * d)
 Substituting the values:
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 a = -77268 mi / h ^ 2
 its stopping distance on a roadway sloping downward at an angle of 17.0 ° is:
 First you must make a free body diagram and see the acceleration of the car:
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