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Fofino [41]
3 years ago
13

A type O star is likely to appear _____. yellow, blue, green or red

Physics
2 answers:
stira [4]3 years ago
7 0

Answer: BLUE

Explanation:

got it right in my quiz

Murljashka [212]3 years ago
5 0
A type O star is likely to appear blue. 
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biome is ecosystem with similar

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A piece of purple plastic is charged with 3. 13×106 extra electrons compared to its neutral state. what is its net electric char
horsena [70]

A piece of purple plastic is charged with 3. 13×106 extra electrons compared to its neutral state, then the net electric charge in coulomb would be - 5.008×10⁻¹³ coulombs.

<h3>What is an electric charge?</h3>

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge (commonly carried by protons and electrons respectively). Unlike charges attract one another while like charges repel one another. We refer to an object as neutral if it has no net charge.

The charge on one electron is -1.6 ×10⁻¹⁹ coulomb.

Then the charge on the 3.13×10⁶ extra electrons compared to its neutral state

=-1.6×10⁻¹⁹ ×(3.13×10⁶)

As given in the problem A piece of purple plastic is charged with 3.13×10⁶ extra electrons compared to its neutral state then the net electric charge in coulombs would be - 5.008×10⁻¹³ coulombs.

Learn more about an electric charge from here

brainly.com/question/8163163

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4 0
2 years ago
Which of these four liquids is a mixture, made of parts, some of which can be separated by filtration? A) salt water B) skimmed
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find the final velocity of the initial velocity of 8m/s with an acceleration of 7 m/s2 over 3 second interval​
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4 0
2 years ago
A uniform meter ruler is balanced at its midpoint
NeTakaya

Answer:

a) i) x = 0.25 m, ii) x = 0.10 m, iii)  x = 0.050 m

b) i)  x = 0.40 m

Explanation:

a) For this exercise we use the rotational equilibrium equation, where we assume that the anticlockwise rotations are positive.

1) L = 2W  

we set our reference system in the center of the bar where the fulcrum is

              ∑τ = 0

              W 0.50 - L x = 0

              x = 0.50 W / L

we substitute the value

              x = 0.50 W / 2W

              x = 0.25 m

ii) L = 5W

we calculate

              x = 0.50 W / 5W

              x = 0.10 m

iii) L = 10 W

               x = 0.50 W / 10W

              x = 0.050 m

b) a new weight is placed at x₂ = 30 cm on the left side

              W 0.50 + W 0.30 - L x = 0

              x = (0.50 + 0.30) W / L

              x = 0.80 W / L

we calculate

i)  L = 2W

                x = 0.80 w / 2w

                x = 0.40 m

4 0
3 years ago
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