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iren2701 [21]
3 years ago
6

!!!!PLEASE HELP!!!3 QUESTION GO TOGETHER

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

i dont know i think (-6,0)

Step-by-step explanation:

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Determine la razón de la siguiente progresión geométrica: 81,27,9,3,1,....
worty [1.4K]

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BẠN BỊ ĐIÊN À

Step-by-step explanation:

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5 0
3 years ago
Need answer with full work
tatyana61 [14]

Answer:

Step-by-step explanation:

x^2 - 17x - 60

(x - 20)(x + 3)

x^2 + 3x - 20x - 60

x^2 - 17x - 60

(x + 20) is not one of the factors

using F.O.I.L., it would have been

x^2 + 17x - 60

4 0
3 years ago
Using the digits 1 to 9, at most one time each, fill in the blanks to make two different pairs of two-digit numbers that have a
agasfer [191]
Do you mean no repeating numbers within the two sets? Because if so, I don't think it's possible.

I started by trying to figure out what the numbers in the tenths place should be. I used subtraction: 71 - ___ = ____. If you try it out, you can't subtract anything with a 6, 7, 8, or 9 in the tenths place because it will leave you with 11 (a repeating digit number), 10 (has a 0), or less (1-digit numbers). Also, a 3 cannot go into the tenths place because when you do 71 - 3_ , your answer will always begin with a 3 (problem because the 3 repeats), or it will contain a 0. 

Therefore, the numbers left for the tenths place are: 1, 2, 4, and 5. 1 and 5 pair up, leaving 4 and 2.
71 - 5_ = 1_   and 71 - 4_ = 2_.

Then, I tried to figure out what numbers go in the ones place. That lead me to realize they act in pairs. The pairs possible in the ones place are 2 and 9, 3 and 8, 4 and 7, 5 and 6. These numbers always go together to result with the final "1" in the "71". Using this information, I looked at the numbers I already used: 1, 2, 4, and 5. Now, looking at the pairs, I eliminated the pairs containing a number already used. This leaves me with only one pair: 3 and 8. Obviously, you need two more pairs to solve the problem, which leads me to my point of saying: This problem is impossible to solve.

I really hope someone can prove me wrong! But this is the solution I have reached for now. :)
4 0
3 years ago
Find AB<br> Round to the nearest tenth.
zimovet [89]
19.2
To find the hypotenuse the equation would be: a^2 + b^2 = c^2.
12 squared is 144 and 15 squared is 225. Add them and you get 369. Then, square root 369 to isolate c. It'd be about 19.2
6 0
3 years ago
Urgent ASAP answer!!
UkoKoshka [18]
C.

not sure, goodluck. sorry if it’s wrong:)
5 0
3 years ago
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