Answer:
(−4, 12), (1, −3)
Step-by-step explanation:
y = −3x
x^2 −4 = y
so
x^2 −4 = −3x
x^2 + 3x - 4 = 0
(x + 4)(x - 1) = 0
x + 4 = 0; x = -4
x - 1 = 0; x = 1
when x = 1, y = -3(1) = -3
when x = -4, y = -3(-4) = 12
Answer
(-4 , 12), (1 , -3)
Answer:
4/9 = 44/99
10/11 = 90/99
Step-by-step explanation:
44/99=90/99
Answer:
24
Step-by-step explanation:
f(n) = f(n − 1) + 3
if n = 7 => f(7) = f(7-1) + 3 = f(6) + 3
if n = 6 => f(6) = f(6-1) + 3 = f(5) + 3
if n = 5 => f(5) = f(5-1) + 3 = f(4) + 3
if n = 4 => f(4) = f(4-1) + 3 = f(3) + 3
if n = 3 => f(3) = f(3-1) + 3 = f(2) + 3
if n = 2 => f(2) = f(2-1) + 3 = f(1) + 3
if f(1) = 6 then f(2) = 9
f(3) = 12
f(4) = 15
f(5) = 18
f(6) = 21
f(7) = 24
<span>Table
Bottles Price($)
3 78
6 156
9 234
From that you can find the unit price: 78 / 3 = 156 / 6 = 234 / 9 = 26.
That means that the unit rate of this fragance is $26.
If you call x the number of bottles the equation is
Price = unit rate * number of bottles = 26x.
Now compare this information with that on your graph to compare the unit rates.
This can help you fo find the unit rate in from your grpah: the unit rate is the slope of the line =
[change in y-coordinate] / [change in the x-coordinate]
</span>
We can write the function in terms of y rather than h(x)
so that:
y = 3 (5)^x
A. The rate of change is simply calculated as:
r = (y2 – y1) / (x2 – x1) where r stands for rate
Section A:
rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)
rA = 12
Section B:
rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)
rB = 300
B. We take the ratio of rB / rA:
rB/rA = 300 / 12
rB/rA = 25
So we see that the rate of change of section B is 25
times greater than A
