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Yuki888 [10]
3 years ago
9

A child goes down a slide, starting from rest. If the length of the slide is 2 m and it takes the child 3 seconds to go down the

slide, what is the child's acceleration?
Physics
1 answer:
Nitella [24]3 years ago
5 0

Answer:

<em>0.44 m/s^2</em>

Explanation:

initial velocity = 0  (since the child starts from rest)

distance covered by the child = 2 m (the length of the slide)

time taken = 3 sec

acceleration of the child = ?

using Newton's equation of motion

s = ut + \frac{1}{2}at^{2}

where s is the distance covered by the child

u is the initial velocity

a is the acceleration

t is the time spent

substituting values, we have

2 = 0(3) + \frac{1}{2}a*3^{2}

2 = 9a/2

4  = 9a

a = 4/9 = <em>0.44 m/s^2</em>

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Thank you for posting your question here at brainly. Below is the answer:

sum of Mc = 0 = -Ay(4.2 + 3cos(59)) + (275)(2.1 + 3cos(59)) + M 
<span>- Ay = (M + (275*(2.1 + 3cos(59)))/(4.2 + 3cos(59)) </span>

<span>sum of Ma = 0 = (-275)(2.1) - Cy(4.2 + 3cos(59)) + M </span>
<span>- Cy = (M - (275*2.1))/(4.2 + 3cos(59)) </span>

<span>Ay + Cy = 275 = ((M+1002.41)+(M-577.5))/(5.745) </span>
<span>= (2M + 424.91)/(5.745) </span>

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<span>Is it maybe supposed to be Ay - Cy = 275</span>
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