Question

A child goes down a slide, starting from rest. If the length of the slide is 2 m and it takes the child 3 seconds to go down the slide, what is the child's acceleration?

Answer 1

Answer:

0.44 m/s^2

Explanation:

initial velocity = 0  (since the child starts from rest)

distance covered by the child = 2 m (the length of the slide)

time taken = 3 sec

acceleration of the child = ?

using Newton's equation of motion

s = $ut + \frac{1}{2}at^{2}$

where s is the distance covered by the child

u is the initial velocity

a is the acceleration

t is the time spent

substituting values, we have

2 = 0(3) + $\frac{1}{2}a*3^{2}$

2 = 9a/2

4  = 9a

a = 4/9 = 0.44 m/s^2