A child goes down a slide, starting from rest. If the length of the slide is 2 m and it takes the child 3 seconds to go down the
1 answer:
Answer:
<em>0.44 m/s^2</em>
Explanation:
initial velocity = 0 (since the child starts from rest)
distance covered by the child = 2 m (the length of the slide)
time taken = 3 sec
acceleration of the child = ?
using Newton's equation of motion
s =
where s is the distance covered by the child
u is the initial velocity
a is the acceleration
t is the time spent
substituting values, we have
2 = 0(3) +
2 = 9a/2
4 = 9a
a = 4/9 = <em>0.44 m/s^2</em>
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Answer:
Explanation:
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Answer:
The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.
See attachment below for full solution
Explanation:
This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.
