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marusya05 [52]
3 years ago
11

A flight attendant pushes a beverage car on an aircraft. Her mass is 75 kg and the cart’s mass is 27 kg. Calculate the accelerat

ion produced when the flight attendant exerts a backward force of 155 N on the floor. All forces opposing the motion, such as friction on the cart’s wheels and air resistance, total 18 N.
Physics
1 answer:
tankabanditka [31]3 years ago
6 0

Answer:

a = 1.34 m/s²

Explanation:

given,

mass of the attendant(M) = 75 Kg

mass of cart (m)= 27 Kg

Backward force exerted on floor (F)= 155 N

frictional force on the cart (f)= 18 N

acceleration

a = \dfrac{F_{net}}{M+m}

F_{net} = F - frictional force

F_{net} = 155 N - 18 N

F_{net} = 137 N

now,

a = \dfrac{137}{75 + 27}

a = \dfrac{137}{102}

a = 1.34 m/s²

the acceleration produced when flight attendant is equal to  a = 1.34 m/s²

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777dan777 [17]

Answer:

605 km

Explanation:

Hello

the same units of measure should be used, then

Step 1

convert  42 m/s ⇒   km/h

1 km =1000 m

1 h = 36000 sec

42 \frac{m}{s}*\frac{1\ km}{1000\ m}=0.042\ \frac{km}{s}\\ 0.042\ \frac{km}{s}\\

0.042\ \frac{km}{s}*\frac{3600\ s}{1\ h} =151.2 \frac{km}{h}\\ \\Velocity =151.2\ \frac{km}{h}

Step 2

find kilometers traveled after 4  hours

V=\frac{s}{t}\\ \\

V,velocity

s, distance traveled

t. time

now, isolating s

V=\frac{s}{t} \\s=V * t\\

and replacing

s=V * t\\s=151.2\frac{km}{h}*4 hours\\ s=604.8 km\\

S=604.8 Km

Have a great day

4 0
3 years ago
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Vsevolod [243]

Answer:

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Explanation:

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The SI unit of power is the
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3 0
3 years ago
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An ideal spring is mounted horizontally, with its left end fixed. The force constant of the spring is 170 N/m. A glider of mass
gizmo_the_mogwai [7]

Answer:

Explanation:

First of all we shall find the velocity at equilibrium point of mass 1.2 kg .

It will be ω A , where ω is angular frequency and A is amplitude .

ω = √ ( k / m )

= √ (170 / 1.2 )

= 11.90 rad /s

amplitude A = .045 m

velocity at middle point ( maximum velocity ) = 11.9 x .045 m /s

= .5355 m /s

At middle point , no force acts so we can apply law of conservation of momentum

m₁ v₁ = ( m₁ + m₂ ) v

1.2 x .5355 = ( 1.2 + .48 ) x v

v = .3825 m /s

= 38.25 cm /s

Let new amplitude be A₁ .

1/2 m v² = 1/2 k A₁²

( 1.2 + .48 ) x v² = 170 x A₁²

( 1.2 + .48 ) x .3825² = 170 x A₁²

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7 0
3 years ago
A- what constant acceleration, in SI units, must a car have to gofrom zero to 60 mph in 10 s?
umka2103 [35]

Answer:

(a) 0.017m/s^2

(b) 17/100,000

(c) 0.17m, 0.558ft

Explanation:

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Acceleration (a) = speed ÷ time = 0.017m/s ÷ 10s = 0.0017m/s^2

(b) g = 9.8m/s^2, a = 0.0017m/s^2

a/g = 0.0017/9.8 = 0.00017 = 17/100,000

(c) Distance = speed × time = 0.017m/s × 10s = 0.17m

Distance in foot = 0.17 × 3.2808ft = 0.558ft

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