Answer:
t = 12.82s
Explanation:
F = m×a
= (70)×(2)
= 140 N
during the acceleration, the sprinter cover d = 29 m with time:
d = 1/2×at
29 = 1/2×(2)×t^2
t^2 = 29s
t = 5.39s
and attains the velocity of:
v = a×t
= 2×5.39
= 10.77 m/s
Then,to cover the last x = 80 m with a speed of 10.77 m/s in time:
t = x/v
= 80/10.77
= 7.43s
Therefore, it will take the sprinter 7.43 + 5.39 = 12.82s
Answer:
Solution
Explanation:
Solution:-
- The direction of motion of bus and car can be denoted by velocity vectors ( v1 and v2 ) respectively.
- On a page draw the velocity vector v1 vertically up denoting the direction of motion of bus from origin
- Similarly,draw the velocity vector v1 horizontally left denoting the direction of motion of car from origin.
- The force exerted by the car-bus interaction is always in the direction of motion.
- The force exerted by the bus is parallel to velocity vector as F1 and force exerted by the car is parallel to velocity vector as F2.
- The vector addition of of the two forces ( F1 and F2 ) will tell us the direction and magnitude of resultant force due to car-bus interaction.
- The resultant force will cause the car to be pushed off the road in the direction shown in the diagram.
Your correct answer would be B.
Hope this helps!
The third law<span> states that for every action (force) in nature there is an equal and opposite reaction.
Hope this helps :D</span>
Complete Question
The question image is in the first uploaded image
Answer:
Explanation:
From the question we are told that
Distance b/w Q mid point and P is given as x
Generally the equation for magnitude of the electric field at the point P is given as
where
Therefore
Therefore equation for magnitude of the electric field at the point P is
