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Phantasy [73]
2 years ago
14

An 11-inch by 8-inch piece of cardboard has squares cut out of the corners and is folded up to make an open-top box. If the volu

me of the box is to be 14 cubic inches, what should be the length of the side of the cut-out corner squares?
A. No solution is possible
B. Either 3.5 inches or approximately 5.8284 inches
C. Either 3.5 inches or approximately 0.1716 inches
D. Exactly 3.5 inches
Mathematics
1 answer:
12345 [234]2 years ago
6 0
  • Volume=14in^3

\\ \sf{:}\implies (side)^3=14

\\ \sf{:}\implies side=\sqrt[3]{14}

\\ \sf{:}\implies side=2.5in

Now

  • L=11in
  • B=8in

\\ \sf{:}\implies Area=11(8)=88in^2

Cut it into 10 parts as per question(Open side means five sides hence it will be 5×2=10)

\\ \sf{:}\implies 88/10=8.8in

Now divide by previous side

\\ \sf{:}\implies \dfrac{8.8}{2.5}=3.52=3.5

Option D

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Area of Consuela's rectangular living room = 360 square feet
Let us assume the the length of the living room = x
Then
width of the living room = (5/8) * x
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Then
Area of the rectangle = Length * Width
360 = x * (5x/8)
360 = 5x^2/8
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x = 24
Then
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The Width of the rectangle is = 24 * (5/8) inches
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Hey there!

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