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DiKsa [7]
3 years ago
13

If 50.0 g of silicon dioxide is heated with an excess of carbon, 27.9 g of silicon carbide is produced. What is the percent yiel

d of the reaction
Chemistry
1 answer:
Molodets [167]3 years ago
6 0

Answer: The percent yield of the reaction is 83.5 %

Explanation:

The given balanced equation is

SiO_2+3C\rightarrow SiC+2CO

SiO_2 is the limiting reagent as it limits the formation of product and C is the excess reagent.

According to stoichiometry :

60.08 g of SiO_2 produce = 40.11 of SiC

Thus 50.0 of SiO_2 will produce=\frac{40.11}{60.08}\times 50.0=33.4  of SiC

 Experimental yield of SiC = 27.9 g

Percent yield = \frac{\text {Experimental yield}}{\text {theoretical yield}}\times 100=\frac{27.9g}{33.4g}\times 100=83.5\%

Thus  percent yield of the reaction is 83.5 %

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Balance the chemical equation below: CO2 + H2O + 2678 kJ-> C6H1206 + O2 a. How many moles of H20 are involved in this reactio
11Alexandr11 [23.1K]

Answer:

a) 6 mol H2O

b) this reaction is endothermic

c) when 1 mol of CO2 is used, in the reaction they occur 0.5025 KJ

Explanation:

balanced eq:

  • 6CO2 + 6H2O + 2678 KJ ↔ C6H12O6 + 6O2

                                         6 - C - 6

                                         18 - O - 18

                                          12 - H - 12

a) mol H2O = 6 mol.......from balanced equation.

b) ΔE = 2678 KJ....... this reaction absorbs heat ( ΔE is positive )

c)    1 gramo C6H12O6 ≅ 4 cal

  • Mw C6H12O6 = 180.156 g/mol

⇒ 1mol CO2 * ( mol C6H12O6 / 6mol CO2 ) =0.166 mol C6H12O6

⇒ 0.166mol C6H12O6 * ( 180.156 g C6H12O6 / mol ) = 30.026g C6H12O6

⇒30.026 gC6H12O6 * ( 4 cal / gC6H12O6 ) * ( Kcal / 1000 cal ) * (4184 J / Kcal ) * ( KJ / 1000 J ) = 0.5025 KJ C6H12O6.

8 0
3 years ago
Boyle’s law relates to volume and?
fgiga [73]

Answer:

pressure

Explanation:

Boyle's law states that "the volume of a given mass of gas is inversely proportional to the pressure provided the temperature remains constant"

3 0
3 years ago
The reaction below shows how silver chloride can be synthesized. AgNO3 NaCl Right arrow. NaNO3 AgCl How many moles of silver chl
Otrada [13]

From 15 mol of Silver nitrate, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.

The balanced chemical reaction for the synthesis of silver chloride has been:

\rm AgNO_3\;+\;NaCl\;\rightarrow\;AgCl\;+\;NaNO_3

From the balanced equation, since there has presence equal moles of silver nitrate and sodium chloride, the moles of silver chloride formed has been equivalent. Thus, 1 mole of silver nitrate gives 1 mole of silver chloride.

The moles of silver nitrate available are,  \rm M_A_g_N_O_3=15\;mol

The moles of silver nitrate produced can be given as:

\rm 1\;mol\;AgNO_3=1\;mol\;AgCl\\15\;mol\;AgNO_3=15\;\times\;1\;mol\;AgCl\\15\;mol\;AgNO_3=15\;mol\;AgCl

Thus, the moles of silver chloride produced have been 15 mol. Thus, option B is correct.

For more information about moles produced, refer to the link:

brainly.com/question/10606802

7 0
2 years ago
Read 2 more answers
The complete combustion of propane (C3H8) in the presence of oxygen yields CO2 and H2O: C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (g) a
mixas84 [53]

Answer:

26.9 L is the volume of CO₂, we obtained

Explanation:

The reaction is: C₃H₈(g) + 5O₂(g)  →  3CO₂ (g) + 4H₂O (g)

Let's determine the reactants moles:

27.5 g . 1mol / 44 g = 0.625 moles

We need density of O₂ to determine mass and then, the moles.

O₂ density = O₂ mass / O₂ volume

O₂ density . O₂ volume = O₂ mass

1.429 g/L . 45L = O₂ mass → 64.3 g

Moles of O₂ → 64.3 g . 1mol/32g = 2.009 moles

Let's find out the limiting reactant:

1 mol of propane needs 5 moles of oxygen to react

Then, 0.625 moles will react with (0.625 . 5)/1 = 3.125 moles of O₂

Oxygen is the limiting reactant, we need 3.125 moles but we only have 2.009 moles

Ratio is 5:3. 5 moles of O₂ produce 3 moles of CO₂

Therefore, 2.009 moles of O₂ must produce (2.009 .3) /5 = 1.21 moles of CO₂. Let's find out the volume, by Ideal Gases Law (STP are 1 atm and 273K, the standard conditions)

1 atm . V = 1.21 moles . 0.082 . 273K

V = (1.21 moles . 0.082 . 273K) / 1atm = 26.9 L

3 0
3 years ago
You mix a blue and a clear liquid together and they turn bright green. Has a chemical reaction occurred?
Margarita [4]
Yes because color change is a sign of a chemical reaction.
7 0
3 years ago
Read 2 more answers
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