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DiKsa [7]
2 years ago
13

If 50.0 g of silicon dioxide is heated with an excess of carbon, 27.9 g of silicon carbide is produced. What is the percent yiel

d of the reaction
Chemistry
1 answer:
Molodets [167]2 years ago
6 0

Answer: The percent yield of the reaction is 83.5 %

Explanation:

The given balanced equation is

SiO_2+3C\rightarrow SiC+2CO

SiO_2 is the limiting reagent as it limits the formation of product and C is the excess reagent.

According to stoichiometry :

60.08 g of SiO_2 produce = 40.11 of SiC

Thus 50.0 of SiO_2 will produce=\frac{40.11}{60.08}\times 50.0=33.4  of SiC

 Experimental yield of SiC = 27.9 g

Percent yield = \frac{\text {Experimental yield}}{\text {theoretical yield}}\times 100=\frac{27.9g}{33.4g}\times 100=83.5\%

Thus  percent yield of the reaction is 83.5 %

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A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added, and the
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Since they are telling us that the equivalence point was reached after 17.0 mL of   2.5 M HCl were added , we can calculate the number of moles of HCl which neutralized our unknown hydroxide.

Now all the choices for the metal cation are monovalent, therefore the general formula for our unknown is XOH and  we know the reaction is 1 equivalent acid to 1 equivalent base. Thus we have the number of moles, n,  of XOH and from the relation n = M/MW we can calculate the molecular weight of XOH.

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0.0425X = 4.36 -0.7225 = 3.6375

X = 3.6375/0.0425 = 85.59

The unknown alkali is Rb which has an atomic weight of 85.47 g/mol

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