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Olin [163]
3 years ago
14

A gas that exerts a pressure of 537 torr in a container with a volume of 5.30 L will exert a pressure of 255 torr when transferr

ed to a container with a volume of ? L
Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:- The gas needs to be transferred to a container with a volume of 11.2 L.

Solution:- From Boyle's law. "At constant temperature, Volume is inversely proportional to the pressure."

It means, the volume is decreased if the pressure is increased and vice versa.

Here, the Pressure is decreasing from 537 torr to 255 torr. So, the volume must increase and calculated by using the equation:

P_1V_1=P_2V_2

Where, P_1 is initial pressure and P_2 is final pressure. Similarly, V_1 is initial volume and V_2 is final volume.

Let's plug in the values in the equation:

(537 torr)(5.30 L) = (255 torr)(V_2)

V_2=(\frac{537 torr*5.30 L}{255 torr})

V_2 = 11.2 L

So, the new volume of the container needs to be 11.2 L.

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Answer: 9.9 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{8.150g}{2g/mol}=4.08moles

b) moles of C_2H_4

\text{Number of moles}=\frac{9.330g}{28g/mol}=0.33moles

H_2(g)+C_2H_4(g)\rightarrow C_2H_6(g)

According to stoichiometry :

1 mole of C_2H_4 combine with 1 mole of H_2

Thus 0.33 mole of C_2H_4 will combine with =\frac{1}{1}\times 0.33=0.33 mole of H_2

Thus C_2H_4 is the limiting reagent as it limits the formation of product.

As 1 mole of C_2H_4 give =  1 mole of C_2H_6

Thus 0.33 moles of C_2H_4 give =\frac{1}{1}\times 0.33=0.33moles  of C_2H_6

Mass of C_2H_6=moles\times {\text {Molar mass}}=0.33moles\times 30g/mol=9.9g

Thus theoretical yield (g) of C_2H_6 produced by the reaction is 9.9 grams

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3 years ago
An example of a double replacement chemical reaction takes place in batteries. In an alkaline battery, Manganese oxide reacts wi
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3 years ago
Plz do this i need help ill give u brailiest
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1. C

2. B

3. B

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A sample of oxide iron weighing 2.40g was heated in a stream of hydrogen until it was completely converted to the metal. If the
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Answer:

Fe₂O₃

Explanation:

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<em>Moles Fe:</em>

1.68g * (1mol / 56g)  =0.03moles

<em>Moles O:</em>

2.40g-1.68g = 0.72g * (1mol/16g) = 0.045moles

The ratio O/Fe is:

0.045moles / 0.03moles = 1.5 moles. this ratio is obtained if the formula is:

<h3>Fe₂O₃</h3>
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3 years ago
the atomic number tells you the number of _______ in one atom of an element. It also tells you the number of ______ in a neutral
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Answer:

Protons, electrons, same in that order is the answer.

Explanation:

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