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Illusion [34]
4 years ago
7

Which of these expressions are correct variations of the combined gas law?

Chemistry
2 answers:
Firdavs [7]4 years ago
4 0

Answer:

Both p2=p1(t2/t1)(v1/v2) and p1v1t2=p2v2t1

Explanation:

victus00 [196]4 years ago
3 0
The combines law of gas is:

P1 * V1     P2 * V2
---------- = -----------
    T1           T2

So, you can obtain many equivalent valid forms depending on the variable that you solve for.

These are some examples:

Solve for T1:

T1 = T2 * (P1 * V1) / (P2 * V2)

Solve for V2:

V2 = V1 * (T2 / T1) * (P1 / P2)

Solve for P1:

P1 = P2 * (T1 / T2) * ( V2 / V1)
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You are asked to write observations about a 100g sample of Nitrogen-16 before it decays, but you're running late. In order to ma
san4es73 [151]

Answer:

You cannot make observations if you are 57 seconds late into the lab.

Explanation:

The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.

Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.

The half life equation is;

N_t = N₀(½)^(t/t_½)

Where:

t = duration of decay

t_½ = half-life

N₀ = number of radioactive atoms initially

N_t = number of radioactive atoms remaining after decay over time t

We are given;

t = 57 secs

N₀ = 100 g

Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2

Thus;

N_t = 100(1/2)^(57/7.2)

N_t = 0.4139g

We are told that In order to make observations, you require at least .5g of material.

The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.

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