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tamaranim1 [39]
3 years ago
8

A steel alloy specimen having a rectangular cross section of dimensions 18.1 mm × 3.0 mm ( 0.7126 in. × 0.1181 in.) has the stre

ss-strain behavior shown in the Animated Figure 6.22b. If this specimen is subjected to a tensile force of 90140 N ( 20260 lbf) then (a) Determine the amount of elastic strain induced. (b) Determine the amount of plastic strain induced. (c) If its original length is 770 mm, what will be its final length after this force is applied and then released? The elastic modulus for steel is 207 GPa.
Physics
1 answer:
Natalka [10]3 years ago
4 0

Answer:

Your search - A steel alloy specimen having a rectangular cross section of dimensions 18.1 mm × 3.0 mm ... - did not match any documents.

Suggestions:

Make sure that all words are spelled correctly.

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Explanation:

i hope it help please mark me as a brainless

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Vikentia [17]
Given that 2 m is to .10N

we will set up a ratio & proportion

.10 x
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2x = .10(1)

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3 years ago
1. A heat engine operates between two reservoirs at T2 = 600 K and T1 = 350 K. It takes in 1.00 x 103 J of energy from the highe
Alex73 [517]

Answer:

\Delta S_u=2.1429\ J.K^{-1}

W_c=416.67\ J

Explanation:

Given:

temperature of source reservoir, T_H=600\ K

temperature of sink reservoir, T_L=350\ K

energy absorbed from the source, Q_{in}=1000\ J

work done, W=250\ J

a.

<u>Now change in entropy of the surrounding:</u>

\Delta S_u=\frac{dQ_L}{T_L}

<em>Since heat engine is a device that absorbs heat from a high temperature reservoir and does some work giving out heat in the universe as the byproduct.</em>

\Delta S_u=\frac{Q_H-W}{T_L}

\Delta S_u=\frac{1000-250}{350}

\Delta S_u=2.1429\ J.K^{-1}

b.

<u>We know Carnot efficiency is given as:</u>

\eta_c=1-\frac{T_L}{T_H}

\eta_c=1-\frac{350}{600}

\eta_c=0.4167

<u>Now the Carnot work done:</u>

W_c=Q_H\times \eta_c

W_c=1000\times 0.4167

W_c=416.67\ J .......................(1)

c.

From eq. (1) we have the Carnot work, so the difference:

\Delta W=W_c-W

\Delta W=416.67-250

\Delta W=166.67\ J

Now, we find:

T_L.\Delta S_u=350\times 2.1429

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3 years ago
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luda_lava [24]
The answer to the question is A
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Svetradugi [14.3K]

Answer:

120 mph

Explanation:

Given:

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v₀ = 0 mi/s

t = 15 s

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Δx = ½ (v + v₀) t

0.25 mi = ½ (v + 0 mi/s) (15 s)

v = 0.0333 mi/s

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Explain briefly where the energy come from when a liquid Rises against Gravity in a capillary tube​
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Answer:

Surface tension

Explanation:

When liquid rises against gravity in a capillary tube, the energy comes from surface tension.

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The liquid will be in contact with the capillary tube and as such experiences surface tension which in turn makes the capillary tube to experience an upward force that makes the liquid begin to rise up.

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