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tamaranim1 [39]
3 years ago
8

A steel alloy specimen having a rectangular cross section of dimensions 18.1 mm × 3.0 mm ( 0.7126 in. × 0.1181 in.) has the stre

ss-strain behavior shown in the Animated Figure 6.22b. If this specimen is subjected to a tensile force of 90140 N ( 20260 lbf) then (a) Determine the amount of elastic strain induced. (b) Determine the amount of plastic strain induced. (c) If its original length is 770 mm, what will be its final length after this force is applied and then released? The elastic modulus for steel is 207 GPa.
Physics
1 answer:
Natalka [10]3 years ago
4 0

Answer:

Your search - A steel alloy specimen having a rectangular cross section of dimensions 18.1 mm × 3.0 mm ... - did not match any documents.

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A tennis ball, 0.314 kg, is accelerated at a rate of 164 m/s2 when hit by a professional tennis player. What force does the play
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In a science demonstration, a teacher mixed zinc (Zn) with hydrogen chloride (HCl) in a flask and quickly attached a balloon ove
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Answer:

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Explanation:

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Read 2 more answers
How to solve part (b)?​
maria [59]

Answer:

<em>1.11m</em>

Explanation:

From the diagram we are given the following forces;

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F3 = 30N

Since the sum of upward forces is equal to that of downward force, then;

F2 = F1 + F3

F2 = 24.3N + 30N

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Required

Distance between B and C

First we need to get Length of AC

Take moment about A

Anticlockwise moment = F3 cos20 * AC

Anticlockwise moment = 30ACcos 20

Clockwise moment = 1.2 * F2

Clockwise moment = 1.2(54.3) = 65.16Nm

Applying the principle of moment;

Sum of ACW moment = Sum of CW moments

30ACcos 20 = 65.16

AC = 65.16/30cos20

AC = 65.16/28.19

AC = 2.31m

Get the distance BC

AC = AB + BC

BC = AC-AB

BC = 2.31 - 1.2

BC = 1.11m

Hence the separation between B and C is 1.11m

<em>Note that the force F1 got in (a) was the value used in the calculation.</em>

<em></em>

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