Answer:
1.when it is closest to the sun
2.when it is midway between its farthest
Explanation:
According to the law of Kepler's
T ² ∝ r³
T=Time period
r=semi major axis
We also know that time period T given as

v=Speed







So we can say that ,when r is more then the speed will be minimum and when r is low then speed will be maximum.
Answer:
angular resolution = 0.07270° = 1.269 ×
rad
greatest distance from the camera = 118.20 m = 0.118 km
Explanation:
given data
diameter = 0.50 mm = 0.5 ×
m
distance apart = 15 cm = 15×
m
wavelength λ = 520 nm = 520 ×
m
to find out
angular resolution and greatest distance from the camera
solution
first we expression here angular resolution that is
sin θ =
.......................1
put here value λ is wavelength and d is diameter
we get
sin θ =
θ = 0.07270° = 1.269 ×
rad
and
distance from camera is calculate here as
θ =
.................2
I = 
I = 118.20 m = 0.118 km
Answer:

Explanation:
A = Area = 
B = Magnetic field = 1.7 T
= Angle that magnetic field makes with the plane of the loop = 
t = Time = 0.42 s
EMF is given by

The magnitude of the average emf induced in the loop is
.
Answer:
Mass spectrometry is an analytical technique that measures the mass-to-charge ratio of ions. The results are typically presented as a mass spectrum, a plot of intensity as a function of the mass-to-charge ratio.
Explanation:
Tip your bucket into a mass spectrometer. It turns the atoms into ions Then it will separate the ions by passing them first through an electric field, then through a magnetic field, so they fan out into a spectrum