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mina [271]
2 years ago
9

The acceleration of a block attached to a spring is given by a=−(0.324m/s2)cos([2.50rad/s]t) a = − ( 0.324 m / s 2 ) c o s ( [ 2

.50 r a d / s ] t ) . Part A What is the frequency of the block's motion?
Physics
1 answer:
allsm [11]2 years ago
5 0

Answer:

Looks like you have:

a = -.324 cos 2.5 t

In this case   ω^2 A = .324

ω = 2.5

f = ω / (2 * pi) = 2.5 / 6.28 = .40 / sec

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What is the unit of k (spring constant) in SI system?
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Answer:

SI unit of k (spring constant) = N/m

Explanation:

We have expression for force in a spring extended by x m given by

         F = kx

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Taking units on both sides

         Unit of F = Unit of k x Unit of x

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          Unit of k = N/m

SI unit of k (spring constant) = N/m

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Answer:

a)  The swimmer should travel perpendicular to the bank to minimize the spent in getting to the other side.

b) 133.33 m

c) 53.13°

d) 106.67 m

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a) The swimmer should travel perpendicular to the bank to minimize the spent in getting to the other side.

b) velocity = distance * time

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The swimmer will be carried downstream by the river through a distance, s

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c) To minimize the distance traveled by the swimmer, his resultant velocity must be perpendicular to the velocity of the swimmer relative to water

That is ,

cos \theta = \frac{v_{s} }{v_{r} } \\cos \theta = 1.5/2.5\\cos \theta = 0.6\\\theta = cos^{-1} 0.6\\\theta = 53.13^{0}

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v_{y} = 1.5 sin 53.13\\v_{y} = 1.2 m/s

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the horizontal speed,

v_{x} = 2.5 - 1.5cos53.13\\v_{x} = 1.6 m/s

The downstream horizontal distance of the swimmer, x = v_{x} t

x = 1.6 * 66.67

x = 106.67 m

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