Answer:
1 m
Explanation:
Given
The mirror is a concave mirror.
Radius of curvature = 2 m
Now, for a parallel beam after reflection occurs, the object should be placed at the focus of the mirror.
We know, focal length = radius of curvature / 2
= 2 / 2
= 1
Thus the focal length is 1 m.
Hence the object should be placed at 1 m from the concave mirror for parallel beam reflection.
Answer:
Explanation:
Let that point be at a distance x from q1
Then Kq1/x^2= Kq2/ (s-x)^2
Taking square roots and simplifying, x =s /[1+(q2/q1)^0.5]
Assuming an identical distance, the rigidity of Q on 2Q is equivalent in value to the rigidity of 2Q on Q. for that reason, had the area R been stored an identical, the two forces could be equivalent. inspite of the shown fact that, via fact the area is being decreased, we could constantly consult with the equation we use to calculate those forces: F = ok(Q1xQ2)/(R^2) because R is squared and is being halved, the final result's that's it being divided by potential of a million/4. for that reason, the rigidity would be expanded by potential of four, and be 4F.
The change in gravitational potential energy is A) 15.68 J
Explanation:
The gravitational potential energy of an object is the energy possessed by the object due to its position in the gravitational field.
The change in gravitational potential energy of an object is given by the equation:

where
m is the mass of the object
is the acceleration due to gravity
is the change in height of the object
In this problem, we have
m = 2 kg is the mass of the frame
is the change in height
Substituting, we find:

Learn more about potential energy:
brainly.com/question/1198647
brainly.com/question/10770261
#LearnwithBrainly
Answer:
reaction force/normal force (its when the tables kinda pushing from under so it doesnt fall)
and the notebook wont float bc of gravity
Explanation:
theres a quizlet on this if you wanna check it out lol