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melisa1 [442]
3 years ago
12

. Since the man is walking at a constant velocity, he has what acceleration

Physics
1 answer:
docker41 [41]3 years ago
6 0
If he’s walking at a constant velocity there is no acceleration.
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A fossil mammoth bone was found to contain 6.25% carbon-14 percent isotope and 93.75% nitrogen-14 daughter isotope. If the half-
Effectus [21]

Answer:

The mammoth bone is 22726 years old.

Explanation:

We can find how hold is the mammoth bone using the decay equation:

N(t) = N_{0}*e^{-\lambda t}   (1)

Where:

N(t): is the quantity at time t = 6.25%N₀

N₀: is the initial quantity

λ: is the decay constant

First, we need to find λ:

\lambda = \frac{ln(2)}{t_{1/2}} = \frac{ln(2)}{5700 y} = 1.22 \cdot 10^{-4} y

Now, by solving equation (1) for t we have:

t = \frac{ln(\frac{N(t)}{N_{0}})}{-\lambda} = \frac{ln(0.0625)}{-1.22 \cdot 10^{-4}} = 22726 y      

Therefore, the mammoth bone is 22726 years old.

I hope it helps you!

6 0
3 years ago
an object with a mass of 125 kilograms is lifted through a height of 10 meters. how much work is done?
marissa [1.9K]

(125 kg)*(9.81 m/s^2)*(10 m)  

W = 12262.5 J

8 0
3 years ago
Does h2 have a coefficient?<br><br> A yes<br> B no
sineoko [7]
Since there is no number in front, there is NO coefficient.
B. No
6 0
3 years ago
Two charges that are separated by one meter exert 1-N forces on each other. If the charges are pushed together so the separation
Nana76 [90]

Answer: 16N

Explanation:

According to coulombs law which states that the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically,

F = kq1q2/r²

If two charges that are separated by one meter exert 1-N forces on each other, the equation will become

1 = kq1q2/1²

kq1q2 = 1 ... (1)

If the charges are pushed together so the separation is 25 centimeters, the force between them becomes,

F = kq1q2/0.25² (25cm converted to meters)

0.0625F = kq1q2 ... (2)

Dividing equation 1 by 2 to determine the force F on each charges, it becomes;

1/0.0625F = kq1q2/kq1q2

1/0.0625F = 1

0.0625F = 1

F = 1/0.0625

F= 16N

6 0
4 years ago
Two people are pulling straight down on ropes attached to a wheel. The wheel has a radius of 2.42 m. One person pulls in a clock
natulia [17]

Answer:

69.2 Nm

Explanation:

Since torque, τ = Fd where F = force and d = distance of force from center of wheel.

The torque due to the clockwise force F' = 43.2 N at a distance d' = radius of wheel = 2.42 m (since it is at the end of the wheel) is τ' = F'd' = 43.2 N × 2.42 m = 104.544 Nm. Since this force is counterclockwise, the torque is positive. So, τ' = 104.544 Nm

The torque due to the force F" = 67.8 N at a distance d" = 0.522 m from center of wheel is τ" = F"d" = 67.8 N × 0.522 m = 35.3916 Nm. Since this force is counterclockwise, the torque is negative. So, τ" = -35.3916 Nm

The net torque on the wheel  τ =  τ' +  τ"

= 104.544 Nm + (-35.3916 Nm)

= 104.544 Nm - 35.3916 Nm

= 69.1524 Nm

≅ 69.2 Nm

4 0
3 years ago
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