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2 years ago

A student is investigating potential and kinetic energy by stretching a spring across a table. When the student lets go

Chemistry

2 answers:

Anna11 [10]2 years ago

4 0

Answer: When the spring is recoiling

Explanation:

larisa [96]2 years ago

4 0

Answer:

When the spring is recoiling

Explanation:

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14. Within a single use of the scientific method, which of the following steps can only be performed after data is collected?

Romashka-Z-Leto [24]

A should be the answer.

4 0

2 years ago

The common laboratory solvent ethanol is often used to purify substances dissolved in it. The vapor pressure of ethanol , CH3CH2

OverLord2011 [107]

Answer:

Molar mass of solute is 183.4g/mol

Explanation:

Using Raoult's law it is possible to find moles of solute, thus:

$P_{solution} = X_{solvent}P_{solvent}^0$

Where pressure of solution is 53.15 mmHg, pressure of pure solvent is 54.68 mmHg and mole fraction is:

53.15 mmHg = X 54.68 mmHg

0.9720 = X

Mole fraction of solvent is defined as moles of solvent / total moles.

Moles of solvent are:

286.8g × (1mol / 46.07g) = 6.225 moles of ethanol.

That is:

$0.9720 = \frac{6.225mol}{Y+6.225mol}$

Where Y are moles of solute.

6.051 + 0.9720Y = 6.225

0.9720Y = 0.174

Y = 0.179 moles of solute

As mass of solute dissolved was 32.83g. Molar mass of solute is:

32.83g / 0.179mol = 183.4g/mol

4 0

3 years ago

A solution is prepared by dissolving 0.5636 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliq

zepelin [54]

Answer:

The final molarity of the diluted oxalic acid solution is 0.002504 M

Explanation:

Step 1: Data given

Mass of oxalic acid (H2C2O4) = 0.5636 grams

Volume of the solution = 100.0 mL = 0.100 L

A 10 ml of this solution diluted in 250 ml of solution.

Molecular weight of H2C2O4 = 90.03 g/mol

Step 2: Calculate initial moles of H2C2O4

Moles H2C2O4 = mass / molar mass

Moles H2C2O4 = 0.5636 grams / 90.03 g/mol

Moles H2C2O4 = 0.00626 moles

Step 3: Calculate molarity of the solution

Molarity = moles / volume

Molarity = 0.00626 moles / 0.100 L

Molarity = 0.0626 M

Step 4: Calculate moles of a 10.00 mL aliquot

Moles = 0.0626 M * 0.010 L

Moles = 0.000626 moles

Step 5: Calculate the new molarity

Molarity = 0.000626 moles / 0.250 L

Molarity = 0.002504 M

The final molarity of the diluted oxalic acid solution is 0.002504 M

6 0

2 years ago

The elements fluorine (F), chlorine (Cl), and Iodine are all part of the same ____________________ on the periodic table.

IgorC [24]

Answer:

Halogen Family of elements

Explanation:

Group Seventeen

4 0

2 years ago

Calculate the molarity of an hcl solution if a 10.00 ml sample requires 25.24 ml of a 1.600 m naoh solution to be neutralized.

AlladinOne [14]

Answer:

The molarity of the HCl solution should be 4.04 M

Explanation:

Step 1: Data given

volume of HCl solution = 10.00 mL = 0.01 L

volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L

Step 2: The balanced equation

HCl + NaOH → NaCL + H2O

Step 3: Calculate molarity of HCl

n1*C1*V1 = n2*C2*V2

Since the mole ratio for HCl and NaOH is 1:1 we can just write:

C1*V1 =C2*V2

⇒ with C1 : the molarity of HCl = TO BE DETERMINED

⇒ with V1 = the volume og HCl = 10 mL = 0.01 L

⇒ with C2 = The molarity of NaOH = 1.6 M

⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L

C1 * 0.01 = 1.6 * 0.02524

C1 = (1.6*0.02524)/0.01

C1 = 4.04M

The molarity of the HCl solution should be 4.04 M

6 0

3 years ago