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Fynjy0 [20]
3 years ago
5

What is an empirical formula

Chemistry
2 answers:
yarga [219]3 years ago
8 0
A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.
zlopas [31]3 years ago
6 0

<em>A</em><em>n empirical </em><em> </em><em>shows the simplest </em><em> </em><em>ratio among atoms in a compound</em><em> </em><em>.</em>

<h2><em>More</em><em> </em><em>information</em></h2>

  • <em>an empirical formula</em><em> </em><em>is the simplest formula for a compound </em><em>.</em><em>For</em><em> </em><em>example</em><em>,</em><em> </em><em>H2O2</em><em> </em><em>can be </em><em> </em><em>reduced to a </em><em>si</em><em>mpler</em><em> </em><em>formula</em><em>.</em><em> </em>
  • <em>Determining a Molecular Formula from an Empirical Formula The empirical formula for a compound is P 2 O 5 . Its experimental molar mass is 284 g/mol.</em>
  • <em>For example, the empirical formula of benzene (C5H5) is Qj, - because the mole ratio of carbon am'hydrogen is 1:1.</em>
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Which of the following is a chemical change?
FromTheMoon [43]

<u>Answer:</u>

<em>Silver tarnishing as the silver metal reacts with sulphur is a chemical change.</em>

<u>Explanation:</u>

Tarnishing is the process of chemical change occurring on the surface of objects leading to corrosion or other defects on the surface. The remaining options like dilution, eroding is a physical change where the concentration of salt and rock particles will be decreased, respectively.

Similarly for soil drying also the concentration of water will be decreased leading to a physical change from wetty or dry soil.

But the last option which indicates tarnishing of silver metal on reaction with sulphur is a chemical process as the surface of silver metal will be reacting to sulphur and leads to lose of electrons which leads to corrosion of the surface or tarnishing of silver.

4 0
3 years ago
Read 2 more answers
How are protists different from plants​
kotegsom [21]

Answer/ explanation :

Protist can be multicellular or unicellular organisms

Plants are all multicellular and also exhibit cellular differentiation.

Protist can be autotroph, heterotrophic or decomposer

Plants are only autotrophs because they manufacture their own food through photosynthesis

Protists are microscopic, more diverse and abundant in nature

Plants are big and complex in nature

Nuclear DNA strands in plants are of higher complexity than those of protist

Plants require oxygen for cellular respiration process unlike protist which can be aerobic and some other species facultative anaerobic

Plants only can reproduce asexually through bulbs and tubers as in yam, potatoes while protists reproduce either sexually through meiosis or asexually through simple cell division.

8 0
3 years ago
If 15.00 mL of 0.0100 M Ca(IO3)2 solution are mixed with 0.500 g KI, what is the theoretical yield (in grams) of I2?
n200080 [17]

The theoretical yield of I2 in the reaction would be 0.23 g

<h3>Theoretical yield</h3>

This refers to the stoichiometric yield of a reaction.

From the equation of the reaction:

Ca(IO3)2 + 10 KI + 12 HCl → 6 I2 + CaCl2 + 10 KCl + 6 H2O

The mole ratio of Ca(IO3)2 and I2 is 1: 6

Mole of 15.00 mL, 0.0100 M Ca(IO3)2 = 15/1000 x 0.0100

                                                              = 0.00015 mole

Equivalent mole of I2 = 0.00015 x 6

                                      = 0.009 mole

mass of 0.0009 I2 = 0.0009 x 253.809

                                = 0.23 g

More on stoichiometric calculations can be found here: brainly.com/question/6907332

8 0
2 years ago
A compound decomposes by a first-order process. if 25.0% of the compound decomposes in 60.0 minutes, the half-life of the compou
Tom [10]
Answer:<span>d. 145 minutes
</span>
Half-life is the time needed for a radioactive to decay half of its weight. The formula to find the half-life would be:

Nt= N0 (1/2)^ t/h

Nt= the final mass
N0= the initial mass
t= time passed
h= half-life

If 25.0% of the compound decomposes that means the final mass would be 75% of initial mass. Then the half-live for the compound would be:
Nt= N0 (1/2)^ t/h
75%= 100% * (1/2)^ (60min/h)
3/4= 1/2^(60min/h)
log2 3/4 = log2 1/2^(60min/h)
0.41503749928 = -60min/h
h= -60 min / 0.41503749928= 144.6min 
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2.568%20%5Ctimes%205.8%7D%7B4.186%7D%20" id="TexFormula1" title=" \frac{2.568 \ti
melomori [17]
Using a calculator:

(2.568 x 5.8)/4.186 = 3.5581460…
= 3.56 (3sf)

You didn’t specify the correct number of significant figures needed.
3 0
2 years ago
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