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Fynjy0 [20]
3 years ago
5

What is an empirical formula

Chemistry
2 answers:
yarga [219]3 years ago
8 0
A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.
zlopas [31]3 years ago
6 0

<em>A</em><em>n empirical </em><em> </em><em>shows the simplest </em><em> </em><em>ratio among atoms in a compound</em><em> </em><em>.</em>

<h2><em>More</em><em> </em><em>information</em></h2>

  • <em>an empirical formula</em><em> </em><em>is the simplest formula for a compound </em><em>.</em><em>For</em><em> </em><em>example</em><em>,</em><em> </em><em>H2O2</em><em> </em><em>can be </em><em> </em><em>reduced to a </em><em>si</em><em>mpler</em><em> </em><em>formula</em><em>.</em><em> </em>
  • <em>Determining a Molecular Formula from an Empirical Formula The empirical formula for a compound is P 2 O 5 . Its experimental molar mass is 284 g/mol.</em>
  • <em>For example, the empirical formula of benzene (C5H5) is Qj, - because the mole ratio of carbon am'hydrogen is 1:1.</em>
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What is required in order to determine wether or not an object moves
Stels [109]

Answer:

The answer would be Point of Reference.

In order to determine, whether an object has moved or not, a point of reference is required. The reference point is required to the measure the movement of the object, without a reference point the distance or displacement cannot be obtained. Hence, a reference point is very required to determine, whether the object has moved or not.

(Hope this helps) Sky

7 0
3 years ago
The boiling point of chloroform is 61.7 C. The enthalapy of vaporization is 31.4 kj/mol. Caculate the entropy of vaporization. D
dedylja [7]

Answer:

Δ S = 93.8 J/mol-K

Explanation:

Given,

Boiling point of chloroform = 61.7 °C

                                             = 273 + 61.7 = 334.7 K.

Enthalapy of vapourization = 31.4 kJ/mol.

Using Gibbs free   energy equation

Δ G = Δ H - T (ΔS)

at equilibrium (when the liquid is boiling), Δ G = 0

so,  0 = ΔH - T (Δ S)

      T (Δ S) = Δ H

and ΔS = ΔH / T

Δ S = (31400 J/mol.) / 334.7 K

Δ S = 93.8 J/mol-K

6 0
3 years ago
A sample of air is slowly passed through aqueous Sodium hydroxide and then over heater copper. Which gases are removed by this p
bagirrra123 [75]

Carbon dioxide and oxygen are removed from the air.

Explanation:

When air is passed through aqueous sodium hydroxide solution the carbon dioxide is removed from the air.

First the carbon dioxide will dissolve and react with water to form carbonic acid ( H₂CO₃) :

CO₂ + H₂O → H₂CO₃

The the carbonic acid will react with sodium hydroxide to form sodium carbonate (Na₂CO₃):

H₂CO₃ + 2 NaOH → Na₂CO₃ + 2 H₂O

After this by passing the air over heated cooper the oxygen is removed.

2 Cu + O₂ → 2 CuO

Learn more about:

neutralization reaction

brainly.com/question/2632201

#learnwithBrainly

7 0
3 years ago
I didn’t mean to click that answer I dropped my phone on the computer.
Yanka [14]

its A plant like protist produce oxygen ...

5 0
3 years ago
Q 9 The table lists the steps to clean water for drinking purpose. 1. Adding chlorine tablets to the water.2. Pouring the water
love history [14]

Answer:

1 and 2

Explanation:

when we r adding chlorine to water

the water is clean

8 0
3 years ago
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