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salantis [7]
2 years ago
5

Describe the structure of atoms including the masses, electrical, charges, and locations of protons, neutrons in the nucleus ,an

d electrons in the electron cloud.
Please make the answer short. I don't have a lot of space left on my paper.
Chemistry
1 answer:
steposvetlana [31]2 years ago
3 0

Answer:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).

Explanation:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).

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Help pls!!!!!!!!!!!!!!!!!!!!!!!
schepotkina [342]

Answer:

D a compound

Explanation:

3 0
2 years ago
Read 2 more answers
If the volume is increased the number of collisions per second will decrease or increase
Alinara [238K]

Answer

Decrease

Explanation:

As surface area will also increase the particles are less likely to collide on a regular basis.

7 0
3 years ago
One mole of which of these compounds contains two moles of hydrogen atoms?NaOH H2S NH3 CH4
Nookie1986 [14]

Answer:

H2S.

Explanation:

That would be H2S,  hydrogen sulphide. (Smells like bad eggs!).

8 0
2 years ago
How many moles of copper Il sulfide can be produced from 2.8 moles of sulfur? Cu + S --> CuS​
Kamila [148]

Answer: 2.8 moles of copper (Il) sulfide (CuS) will be produced from 2.8 moles of sulphur.

Explanation:

The balanced chemical reaction is:

Cu+S\rightarrow CuS  

According to stoichiometry :

1 mole of S produce =  1 mole of copper (Il) sulfide (CuS)

Thus 2.8 moles of S will produce=\frac{1}{1}\times 2.8=2.8moles of copper (Il) sulfide (CuS)

Thus 2.8 moles of copper (Il) sulfide (CuS) will be produced from 2.8 moles of sulphur.

5 0
3 years ago
the molar enthalpy of formation of carbondioxide is -393kjmol. calculate the heat released by the burning of 0.327g of carbon to
Arte-miy333 [17]

This is equivalent to having a standard enthalpy change of reaction equal to  10.611 kJ

<u>Explanation</u>:

The standard enthalpy change of reaction,  Δ H ∘ , is given to you in kilojoules per mole, which means that it corresponds to the formation of one mole of carbon dioxide.

                                    C (s]  +  O 2(g] → CO 2(g]

Remember, a negative enthalpy change of reaction tells you that heat is being given off, i.e. the reaction is exothermic.

First to convert  grams of carbon into moles,

use carbon's molar mass(12.011 g).

                    Moles of C = mass in gram / molar mass

                                        = 0.327 g  / 12.011 g

                     Moles of C = 0.027 moles

Now, in order to determine how much heat is released by burning of 0.027 moles of carbon to form carbon-dioxide.

                                        =  0.027 moles C  \times 393 kJ

             Heat released  = 10.611  kJ.

So, when  0.027  moles of carbon react with enough oxygen gas, the reaction will give off  10.611 kJ  of heat.

This is equivalent to having a standard enthalpy change of reaction equal to  10.611 kJ

7 0
3 years ago
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