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3 years ago

In which picture(s) will you find a state of matter that has particles who have more energy than liquid water?

Chemistry

2 answers:

Murrr4er [49]3 years ago

8 0

Gas and steam aka b and c

Flura [38]3 years ago

4 0

This answer is B and C.

Hope this helps someone :)

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Convert 12.64 g of NaOH to moles

Luden [163]

.316 moles just divide by the molar mass of naoh which is 39.997. So 12.64 divived by 39.997 is .3160237. that is 3.16x10-1

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3 years ago

Read 2 more answers

What changes shape but doesn't change volume

OLEGan [10]

Liquids have a definite volume, but not a definite shape. Hope this helps :)

8 0

3 years ago

Electrons are transferred from atoms of to atoms of . This transfer makes the sodium atoms and the phosphorus atoms . As a resul

pashok25 [27]

Answer:

Explanation:

Electrons are transferred from atoms of sodium to atoms of phosophorus. This transfer makes the sodium atoms positive and the phosphorus atoms negative. As a result, the sodium and phosphorus atoms strongly attract each other.

3 0

4 years ago

If an atom has 34 protons and 40 neutrons, what is its mass number? 40 6 74 34

Darya [45]

Protons+Neutrons
34+40= 74

7 0

3 years ago

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If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r

kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)$

Energy absorbed by pork,E = $1.6\times 10^3 kJ$ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

$10\%=\frac{E}{Q}\times 100$

$Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ$

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = $-1.6\times 10^4 kJ$

Moles of propane burnt to produce Q energy =n

$n\times \Delta H_{rxn}=Q$

$n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol$

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

$\frac{1}{3}\times 7.83 mol=23.49 mol$ carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

8 0

3 years ago