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Furkat [3]
3 years ago
10

13) The condenser pressure is 417.4 psig for r-410A and the condenser outlet temperature is 108f. how much subcooling is there i

n the condenser
Physics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

12°F

Explanation:

Calculation for how much subcooling is there in the condenser

Since the CONDENSING TEMPERATURE for 417.4 psig discharge pressure is 120 degrees (120°) which means that the amount of subcooling that is there in the condenser will be calculated using this formula

Amount of Condenser subcooling= Condensing Temperature discharge pressure -Condenser outlet temperature

Let plug in the formula

Amount of Condenser subcooling=120°-108f

Amount of Condenser subcooling=12°F

Therefore the amount of subcooling that is there in the condenser will be 12°F

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g You shine orange laser light that has a wavelength of 600 nm through a narrow slit. The slit forms a diffraction pattern on a
zimovet [89]

Answer:

 λ = 3 10⁻⁷ m,   UV laser

Explanation:

The diffraction phenomenon is described by the expression

         a sin θ = m λ

let's use trigonometry

         tan θ = y / L

as in this phenomenon the angles are small

        tan θ = \frac{sin \ \theta}{cos \ \theta} = sin θ

        sin θ = y / L

we substitute

      a y / L = m  λ

let's apply this equation to the initial data

       a  0.04 / L = 1 600 10⁻⁹

       a / L = 1.5 10⁻⁵

now they tell us that we change the laser and we have y = 0.04 m for m = 2

      a 0.04 / L = 2  λ

       a / L = 50  λ

we solve the two expression is

         1.5 10⁻⁵ = 50  λ

          λ = 1.5 10⁻⁵ / 50

          λ = 3 10⁻⁷ m

    UV laser

3 0
3 years ago
. Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connecte
Umnica [9.8K]

Given :

Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connected with wires as shown in the circuit given in figure. The current flowing in both the circuits is the same.

To Find :

Will the heat produced in both the cases be equal.

Solution :

Heat released is given by :

H = i²Rt

Here, R is resistance and is given by :

R = \dfrac{\rho L}{A}

So,

H = i^2\times \dfrac{\rho L}{A} t\\\\H = \dfrac{i^2\rho Lt}{A}

Now, in the question every thing is constant except for the length of the wire and from above equation heat is directly proportional to the length of the wire.

So, heat produced by Reem's wire is more than Nain one.

Hence, this is the required solution.

7 0
3 years ago
____ can lift the 403,342 ton pioneering spirit crane vessel 10 meters in 30 seconds as if it was a cork. This about 36 GJ if wo
azamat

Answer:   <u>Trough </u> can lift the 403,342 ton pioneering spirit crane vessel 10 meters in 30 seconds as if it was a cork. This about 36 GJ if work and 1 GW of power.

Explanation:

  • Why trough?

Trough is the correct answer because<u> pioneering scale usually abide only on  trough not on the other given options</u>. A long , narrow depression between the waves or ridges is known as a trough. The lower point in the period is the trough.

  • <u>Speed -:</u> Speed is the distance per unit of time that a body moves. It's a quantity scaler that has just magnitude.
  • <u>Wave energy -: </u>The transmission and capture of energy by ocean surface waves is wave energy (or wave power). The energy collected is then used for all sorts of useful work, including the generation of electricity, water desalination, and water pumping.
  • <u>Crest -</u>: A crest point within a cycle on a wave with the highest value of upward displacement. A crest is a point on a surface wave where the medium's displacement is at its height.
  • <u>Amplitude -:</u> The maximum displacement or distance measured from its equilibrium position, moved by a point on a vibrating body or wave, is called amplitude. It is equal to half of the vibration path's length.
  • <u>Period-</u>: The duration T is the time needed to pass a given point for one complete cycle of vibration. The wave length decreases as the frequency of a wave increases.
  • <u>Wavelength-:</u> The distance between two successive crests or troughs of a wave can be described as the wavelength. The frequency is inversely proportional to the wavelength. This implies that the longer the wavelength, the smaller the frequency. Similarly, the shorter the wavelength, the higher the frequency would be.
  • <u>Frequency</u> -: Frequency defines the number of waves in a given amount of time that travel through a fixed location. In the Hertz unit, frequency is normally measured.
  • <u>Information</u> -: A piece of data is a basic fact about the identity or properties of an object, i.e. a portion of its example.
  • <u>Milli -</u>: Milli is known as a merged form meaning 'thousand' (millipede) used in the metric system for unit names equal to one thousandth of the base unit (millimeter) given.

Hence , the answer is <u>TROUGH.</u>

7 0
3 years ago
The quadriceps muscles pull on the patella simultaneously. Below are the forces from each
Nostrana [21]

Based on the calculation of the resultant of vector forces:

  1. the resultant force due to the quadriceps is 1795 N
  2. the resultant force due to the quadriceps is 1975 N. Training and strengthening the vastus medialis results in a greater force of muscle contraction.

<h3>What is the resultant force due to the quadriceps?</h3>

The resultant of more than two vector forces is given by:

  • F = √Fₓ² + Fₙ²

where:

  • Fₓ is the sum of the horizontal components of the forces
  • Fₙ is the sum of the vertical components of the forces
  • Fx = F₁cosθ + F₂cosθ + F₃cosθ + F₄cosθ
  • Fₙ = F₁sinθ + F₂sinθ + F₃sinθ + F₄sinθ
  • F₁ = 680N, θ = 90 = 30 = 120°
  • F₂ = 220 N, θ = 90 + 16 = 106°
  • F₃ = 600 N, θ = 90 + 15 = 105°
  • F₄ = 480 N, θ = 90 - 35 = 55°

then:

Fx = 680 * cos 120 + 220 * cos 106 + 600 * cos 105 + 480 * cos 55

Fx = -280.6 N

Fₙ = 680 * sin 120 + 220 * sin 106 + 600 * sin 105 + 480 * sin 55

Fₙ = 1773.1 N

then:

F = √(-280.6)² + ( 1773.1)²

F = 1795.16 N

F ≈ 1795 N

Therefore, the resultant force due to the quadriceps is 1795 N

<h3>What would happen if the vastus medialis was trained and strengthened to contract with 720N of force?</h3>

From the new information provided:

  • F₁ = 680N, θ = 90 = 30 = 120°
  • F₂ = 220 N, θ = 90 + 16 = 106°
  • F₃ = 600 N, θ = 90 + 15 = 105°
  • F₄ = 720 N, θ = 90 - 35 = 55°

then:

Fx = 680 * cos 120 + 220 * cos 106 + 600 * cos 105 + 720 * cos 55

Fx = -142.95 N

Fₙ = 680 * sin 120 + 220 * sin 106 + 600 * sin 105 + 720 * sin 55

Fₙ = 1969.72 N

then:

F = √(-142.95)² + ( 1969.72)²

F = 1974.9 N

F ≈ 1975 N

Therefore, the resultant force due to the quadriceps is 1975 N.

Training and strengthening the vastus medialis results in a greater force of muscle contraction.

Learn more about resultant of forces at: brainly.com/question/25239010

3 0
2 years ago
Qwertyuiop hhffhhhhf fiuefhasuhs afbauyhsbvzskhbdv
mars1129 [50]

Answer:

gfhvgtrtjrgvfjrrgfrfftuyrisnhdvfcgfridkjhsybvvtfvjfcgvwjfccegvghcvgrcgvrekgvrkgvkvvrvkvfgkerruuyti

4 0
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