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2 years ago

7

If caviar costs $23.44 a pound, then how much is a quarter of a pound?

2 answers:

saul85 [17]2 years ago

7 0

Question

if caviar costs $23.44 a pound, then how much is a quarter of a pound?

Answer:

Hi, There! Frozen is Here to help :)

$5.86 is A Quarter of a pound Is the Correct Answer

Hope this Helps!

$*FrozenVines*$

Musya8 [376]2 years ago

4 0

Answer:

1 pound is equal to 4 quarter pounds so then what you have to do is find the price for 1/4 a pound of caviar. I got the answer 0.010665529 U.S. dollars.

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BRAINLIEST ASAP! PLEASE HELP ME :)

Afina-wow [57]

Answer:

$\large \boxed{\textbf{30.54 yr}}$

Step-by-step explanation:

For species A,

$P =2000e^{0.05t}$

For species B,

$P =5000e^{0.02t}$

When their populations are equal,

$\begin{array}{rcl}2000e^{0.05t} & = & 5000e^{0.02t}\\e^{0.05t} & = & 2.5e^{0.02t}\\0.05t & = & \ln2.5 + 0.02t\\0.05t & = & 0.9163 + 0.02t\\0.03t & = & 0.9163\\t& = & \dfrac{0.9163}{0.03}\\\\& = & \mathbf{30.54}\\\end{array}\\\text{The populations of species A and B will be the same in $\large \boxed{\textbf{30.54 yr}}$}$

The diagram below shows the population of Species A overtaking that of Species B in about 30.5 yr.

3 0

3 years ago

NEED ASAP<br><br> 1. Find the distance between (3√3, √11) and (−5√3, 5√11)

VLD [36.1K]

Answer: $\sqrt20$

Step-by-step explanation

7 0

3 years ago

Layana’s house is located at (2 and two-thirds, 7 and one-third) on a map. The store where she works is located at (–1 and one-t

NeTakaya

We have been given that Layana’s house is located at $(2\frac{2}{3}, 7\frac{1}{3})$ on a map. The store where she works is located at $(-1\frac{1}{3}, 7\frac{1}{3})$ .

We are asked to find the distance from Layana’s home to the store

We will use distance formula to solve our given problem.

Let us convert our given coordinates in improper fractions.

$2\frac{2}{3}\Rightarrow \frac{8}{3}$

$7\frac{1}{3}\Rightarrow \frac{22}{3}$

$-1\frac{1}{3}\Rightarrow -\frac{4}{3}$

Now we will use distance formula to solve our given problem.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of our given point in above formula, we will get:

$D=\sqrt{(\frac{22}{3}-\frac{22}{3})^2+(\frac{8}{3}-(-\frac{4}{3}))^2}$

$D=\sqrt{(0)^2+(\frac{8}{3}+\frac{4}{3})^2}$

$D=\sqrt{0+(\frac{8+4}{3})^2}$

$D=\sqrt{(\frac{12}{3})^2}$

$D=\sqrt{(4)^2}$

$D=4$

Therefore, the distance from Layana's home to the store is 4 units and option A is the correct choice.

3 0

3 years ago

Read 2 more answers

A right △ABC is inscribed in circle k(O, r). Find the radius of this circle if:

natta225 [31]

We have been given that a right △ABC is inscribed in circle k(O, r).

m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.

First of all, we will draw a diagram that represent the given scenario.

We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.

We will use sine to find side AB.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(30^{\circ})=\frac{AC}{AB}$

$\text{sin}(30^{\circ})=\frac{18}{AB}$

$AB=\frac{18}{\text{sin}(30^{\circ})}$

$AB=\frac{18}{0.5}$

$AB=36$

Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is $\frac{36}{2}=18$ .

Therefore, the radius of given circle would be 18 cm.

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3 years ago

Under his cell phone plan, Samuel pays a flat cost of $41.50 per month and $5 per gigabyte. He wants to keep his bill at $52.50

MakcuM [25]

Answer:

512

Step-by-step explanation:

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3 years ago